Question

What is the sound level for a noise that has an intensity of 7.6 × 10-4 watts/m2?

Answer 1

Sound intensity:  7.6 × 10-4 watts/m2?

To solve this problem you have to understand the threshold of hearing (Level) 

Io = 10^−12 W/m²

Solve the problem: 
"LI = 10×log (I / Io) dB = 10×log (7.6×10^−4 / 10^−12) dB"

and the answer is 88.81dB

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Answer 2

Answer:

The sound level for a noise is 88.9 dB.

Step-by-step explanation:

Given : Intensity of noise is  $7.6\times 10^{-4}Wm^{-2}$.  

To find : What is the sound level for a noise?

Solution :

The range of the sound intensity is the threshold of hearing which is

$I_o=1\times 10^{-12}Wm^{-2}$

Intensity of noise is  $I=7.6\times 10^{-4}Wm^{-2}$

The intensity level in  d B  of a sound of intensity  I  is defined as:

$I_s=(10dB)\log_{10}(\frac{I}{I_o})$

Substitute the values,

$I_s=(10dB)\log_{10}(\frac{7.6\times 10^{-4}}{1\times 10^{-12}})$

$I_s=(10dB)\log_{10}({7.6\times 10^{8})$

$I_s=(10dB)(8.89)$

$I_s=88.9dB$

Therefore, The sound level for a noise is 88.9 dB.