Need help with this answer !!!

Mathematics

2 answers:

KengaRu [80]3 years ago

8 0

To find the area of a rectangle, multiple the width by the length.

(And simply the fractions for a simpler equation)

For piece A:
The length 1 and 3/5 can be turned into an improper fraction by multiplying 1 by the denominator (5) and adding it to the numerator (3). 1 and 3/5 = 8/5

(3/4) • (8/5) = area

Multiple the numerators with each other and the denominators with each other (3 times 8 = 24) (4 times 5 = 20)

The area of piece A is 24/20

If you do the same for piece B:

(2/5) • (21/8) = area

The answer is 42/40

vivado [14]3 years ago

8 0

It’s should be I think42/5

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WXYZ is an isosceles trapezoid with legs WX and YZ and a base XY. If the length of WX is 6x+5, the length of XY is 10x+4 and the

pav-90 [236]

WX and ZY make up the legs, as illustrated in the diagram.
Since it is an isosceles trapezoid, the legs are congruent; that means
6x + 5 = 8x - 3
When solving this equation, we do not want a variable on both sides. We will cancel the 6x to avoid negatives:
6x + 5 - 6x = 8x - 3 - 6x
5 = 8x - 3 - 6x
Combine like terms:
5 = 2x - 3
Cancel the 3 by adding:
5 + 3 = 2x - 3 + 3
8 = 2x
Cancel the 2 by dividing:
8/2 = 2x/2
4 = x