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2 years ago

Can someone help me please):

Mathematics

1 answer:

Ray Of Light [21]2 years ago

3 0

Its is a function. mentally connect the dots. run your pencil across the paper parallel to the y-axis. if none of the points have touch the pencil it is a function. another way to check. look at the X value of all the coordinates. if they are all different its a function.

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Solve each system by elimination 5x+y=9 10x-7y=-18 -4x+9y=9 x-3y=-6

tiny-mole [99]

5x + y = 9....multiply by 7
10x - 7y = -18
----------------
35x + 7y = 63 (result of multiplying by 7)
10x - 7y = -18
----------------add
45x = 45
x = 45/45
x = 1

5x + y = 9
5(1) + y = 9
5 + y = 9
y = 9 - 5
y = 4

solution is : (1,4)
=========================
-4x + 9y = 9
x - 3y = -6 ....multiply by 4
----------------
-4x + 9y = 9
4x - 12y = -24 (result of multiplying by 4)
---------------add
- 3y = - 15
y = -15/-3
y = 5

x - 3y = -6
x - 3(5) = -6
x - 15 = -6
x = -6 + 15
x = 9

solution is : (9,5)

3 0

3 years ago

You have in the class 11 boys and 8 girls. You also have 3 seniors, 4 juniors, and 12 sophomores. If you select a student at ran

Daniel [21]

Answer:

Step-by-step explanation:

5 0

2 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Hi lohith my ff play my iD I'd is opBOYS123123

Ganezh [65]

Answer:

Step-by-step explanation:

Password

5 0

2 years ago

Here is a diagram and its corresponding equation. Find the solution to the equation.

Katen [24]

4(x + 7) = 38

Since there is no operation sign between the 4 and parenthesis, it makes it an automatic multiplication problem.

You would use distributive property to multiply each which should leave your equation looking like this afterwards:

4x + 28 = 38
(4 times x and 4 times 7)

You would then solve it like a two step equation,

1. +28 - 28 = 0
2. 38 - 28 = 10

4x = 10

10 divided by 4 = 2.5

x = 2.5

We can recheck our work by substituting in the value of x.

4(2.5 + 7) = 38

10 + 28 = 38

When we substituted in the value, it gave us the correct inequality.

Therefore,
x = 2.5

5 0

1 year ago

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