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nasty-shy [4]
4 years ago
7

How is the Internet Simulator similar to the Actual Internet? How is it different?

Computers and Technology
1 answer:
masya89 [10]4 years ago
4 0
The Internet Simulator is a tool developed by Code.org for our new high school Computer Science Principles class. ... The Internet Simulator was designed to be used in a classroom with students working collaboratively in-person to solve problems.
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Define function print_popcorn_time() with parameter bag_ounces. If bag_ounces is less than 3, print "Too small". If greater than
Lynna [10]

Answer:

def print_popcorn_time(bag_ounces):

 if bag_ounces<3:

   print("Too Small")

 elif bag_ounces>10:

   print("Too Large")

 else:

   bag_ounces = bag_ounces*6

   print("%s Seconds\n" % bag_ounces)    

Explanation:

  • Using Python Programming Language
  • The function is defined to accept an int parameter
  • Within the function body, if...elif and else statements are used to print the desired output
  • note the use of the %s placeholder (formated output) and \n for a new line in the final print statement
4 0
3 years ago
Which of the following is true of how packets are sent through the Internet?
astra-53 [7]

Answer:

It is A: Packet metadata is used to route and reassemble information travelling  through the internet.

Explanation:

Step 1: The Internet works by chopping data into chunks called packets. Each packet then moves through the network in a series of hops. Each packet hops to a local Internet service provider (ISP), a company that offers access to the network -- usually for a fee

Step 2: Entering the network

Each packet hops to a local Internet service provider (ISP), a company that offers access to the network -- usually for a fee.

Step 3: Taking flight

The next hop delivers the packet to a long-haul provider, one of the airlines of cyberspace that quickly carrying data across the world.

Step 4: BGP

These providers use the Border Gateway Protocol to find a route across the many individual networks that together form the Internet.

Step 5: Finding a route

This journey often takes several more hops, which are plotted out one by one as the data packet moves across the Internet.

Step 6: Bad information

For the system to work properly, the BGP information shared among routers cannot contain lies or errors that might cause a packet to go off track – or get lost altogether.

Last step: Arrival

The final hop takes a packet to the recipient, which reassembles all of the packets into a coherent message. A separate message goes back through the network confirming successful delivery.

8 0
4 years ago
Read 2 more answers
2. Consider a 2 GHz processor where two important programs, A and B, take one second each to execute. Each program has a CPI of
allsm [11]

Answer:

program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

Explanation:

Finding number of instructions in A and B using time taken by the original processor :

The clock speed of the original processor is 2 GHz.

which means each clock takes, 1/clockspeed

= 1 / 2GH = 0.5ns

Now, the CPI for this processor is 1.5 for both programs A and B. therefore each instruction takes 1.5 clock cycles.

Let's say there are n instructions in each program.

therefore time taken to execute n instructions

= n * CPI * cycletime = n * 1.5 * 0.5ns

from the question, each program takes 1 sec to execute in the original processor.

therefore

n * 1.5 * 0.5ns = 1sec

n = 1.3333 * 10^9

So, number of instructions in each program is 1.3333 * 10^9

the new processor :

The cycle time for the new processor is 0.6 ns.

Time taken by program A = time taken to execute n instructions

=  n * CPI * cycletime

= 1.3333 * 10^9 * 1.1 * 0.6ns

= 0.88 sec

Time taken by program B = time taken to execute n instructions

= n * CPI * cycletime

= 1.3333 * 10^9 * 1.4 * 0.6

= 1.12 sec

Now, program A runs in 1 sec in the original processor and 0.88 sec in the new processor.

So, the new processor out-perform the original processor on program A.

Program B runs in 1 sec in the original processor and 1.12 sec in the new processor.

So, the original processor is better then the new processor for program B.

5 0
3 years ago
Vivian wants to increase the storage capacity of her computer. Which components should she upgrade?
Nikitich [7]

Answer:

Hard drive

Explanation:

The hard drive is where the operating system, programs and data reside on (unless the data is saved and backed up elsewhere). An older hard drive that uses platters for reading and writing data to it will be slower than a later model solid state device. Newer hard drives have very fast access speeds compared to older units.

4 0
3 years ago
Python 3.8.2 detais
olga2289 [7]

Answer:

me dont know

Explanation:

5 0
3 years ago
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