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2 years ago

In a class of 29 students, 9 play an instrument and 23 play a sport. There are5

Mathematics

1 answer:

GenaCL600 [577]2 years ago

3 0

Answer:

5/23

Step-by-step explanation:

23 play a sport and 5 play both an instrument and a sport so 5 out of 23 play an instrument given that they play a sport

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6 + 12 = 25 - Which value makes the number sentence true? A. 6 B. 7 C. 12 D. 18

max2010maxim [7]

Answer:

Step-by-step explanation:

6+12=18

25-7=18

7 makes the sentance true.

4 0

2 years ago

Phoenix [80]

Answer:

Step-by-step explanation:

If you increase the scale factor by 4, the sides become:

L= 2×4 = 8

W= 3×4 = 12

Now to find the new area:

8 × 12 = 96cm^2

So, a scale factor of 4 would give the rectangle a scale factor of 96.

Hope this helps and have a nice day!

4 0

3 years ago

You have 100 cm of string which can be cut in one place (or not cut at all) and then formed into a circle and a square (or just

Ne4ueva [31]

Answer:

44cm for minimum area and 0 for maximum area (circle)

Step-by-step explanation:

Let's C be the circumference of the circle and S be the circumference of the square. If we cut the string into 2 pieces the total circumferences would be the string length 100cm.

S + C = 100 or S = 100 - C

The side of square is S/4 and radius of the circle is $\frac{C}{2\pi}$

So the area of the square is

$A_S = \frac{S^2}{4^2} = \frac{S^2}{16}$

$A_C = \pi\frac{C^2}{(2\pi)^2} = \frac{C^2}{4\pi}$

Therefore the total area is

$A = A_S + A_C = \frac{S^2}{16} + \frac{C^2}{4\pi}$

We can substitute 100 - C for S

$A = \frac{(100 - C)^2}{16} + \frac{C^2}{4\pi}$

$A = \frac{100^2 - 200C + C^2}{16} + \frac{C^2}{4\pi}$

$A = 625 -12.5C + \frac{C^2}{16} + \frac{C^2}{4\pi}$

$A = 625 -12.5C + C^2(\frac{1}{16} + \frac{1}{4\pi})$

To find the maximum and minimum of this, we can take the first derivative and set that to 0

$A^{'} = -12.5 + 2C(\frac{1}{16} + \frac{1}{4\pi}) = 0$

$C(\frac{1}{8} + \frac{1}{2\pi}) = 12.5$

$C \approx 44 cm$

If we take the 2nd derivative:

$A^{''} = \frac{1}{8} + \frac{1}{2\pi} > 0$

We can see that this is positive, so our cut at 44 cm would yield the minimum area.

The maximum area would be where you not cut anything and use the total string length to use for either square or circle

if C = 100 then $A_C = \frac{C^2}{4\pi} = \frac{100^2}{4\pi} = 795.77 cm^2$

if S = 100 then $A_S = \frac{S^2}{16} = \frac{100^2}{16} = 625 cm^2$

So to yield maximum area, you should not cut at all and use the whole string to form a circle

4 0

3 years ago

The scores listed below are the results from students taking a dexterity test. What is the 75th percentile of these scores? 1, 1

boyakko [2]

The answer is B 2.25

7 0

3 years ago

Read 2 more answers

Odd numbers greater than -40 but less than -28

netineya [11]

-29 -31 -33 -35 -37 -39

7 0

3 years ago