Answer:
P(G) = 0.55
the probability of getting an offspring pea that is green. Is 0.55.
Is the result reasonably close to the value of three fourths that was expected?
No
Expected P(G)= three fourths = 3/4 = 0.75
Estimated P(G) = 0.55
Estimated P(G) is not reasonably close to 0.75
Step-by-step explanation:
Given;
Number of green peas offspring
G = 450
Number of yellow peas offspring
Y = 371
Total number of peas offspring
T = 450+371 = 821
the probability of getting an offspring pea that is green is;
P(G) = Number of green peas offspring/Total number of peas offspring
P(G) = G/T
Substituting the values;
P(G) = 450/821
P(G) = 0.548112058465
P(G) = 0.55
the probability of getting an offspring pea that is green. Is 0.55.
Is the result reasonably close to the value of three fourths that was expected?
No
Expected P(G)= three fourths = 3/4 = 0.75
Estimated P(G) = 0.55
Estimated P(G) is not reasonably close to 0.75
It’s is 6 because I added it all up and all you have to do is division
Answer:
The probability is 0.995 ( approx ).
Step-by-step explanation:
Let X represents the event of baby girl,
The probability of a baby being a girl is, p = 0.469,
So, the probability of a baby who is not a girl is, q = 1 - 0.469 = 0.531,
Also, the total number of experiment, n = 7
Thus, by the binomial distribution formula,
Where, 
The probability that all babies are girl or there is no baby boy,
Hence, the probability that at least one of them is a boy = 1 - P(X=7)
= 1 - 0.00499125661758
= 0.995008743382
≈ 0.995
Answer 97 because the answer is already above
Pls mark brainliest
17.05 I think..
this could be it idrk what it is
