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elixir [45]
3 years ago
7

Constant of proportionality in 3/5y=8x​

Mathematics
1 answer:
insens350 [35]3 years ago
3 0
The answer is 7 hope i helps you
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Jackson purchased a pack of game cards that was on sale for 22% off. The sales tax in his county is 6%. Let y represent the orig
Luda [366]
Y=.22 x .06x

The numbers are in decimal form.
8 0
3 years ago
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The figure shown below is composed of a semicircle and a non-overlapping equilateral triangle and contains a hole that is also c
Sloan [31]

Check the picture below.

since we know the radius of the larger semicircle is 8, thus its diameter is 16, which is the length of one side of the equilateral triangle.  We also know the smaller semicircle has a radius of 1/3, and thus a diameter of 2/3, namely the lenght of one side of the small equilateral triangle.

now, if we just can get the area of the larger figure and the area of the smaller one and subtract the smaller from the larger, we'll be in effect making a hole/gap in the larger and what's leftover is the shaded figure.

\bf \stackrel{\textit{area of a semi-circle}}{A=\cfrac{1}{2}\pi r^2\qquad r=radius}~\hspace{10em}\stackrel{\textit{area of an equilateral triangle}}{A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\stackrel{side's}{length}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\left[ \stackrel{\textit{larger figure}}{\cfrac{1}{2}\pi 8^2~~+~~\cfrac{16^2\sqrt{3}}{4}} \right]\qquad -\qquad \left[ \cfrac{1}{2}\pi \left( \cfrac{1}{3} \right)^2 +\cfrac{\left( \frac{2}{3} \right)^2\sqrt{3}}{4}\right]}

\bf \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\frac{4}{9}\sqrt{3}}{4} \right] \\\\\\ \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\sqrt{3}}{9} \right]~~\approx~~ 211.38 - 0.37~~\approx~~ 211.01

3 0
3 years ago
Write the​ point-slope form of the​ line's equation satisfying the given conditions. Then use the​ point-slope form of the equat
Advocard [28]

Answer:

y - 7 = 4(x - 6)

y - 7 = 4x - 24

y = 4x - 24 + 7

y = 4x - 17

8 0
3 years ago
Read 2 more answers
Suppose f(x) = x^2 and
SpyIntel [72]

Given:

The two functions are:

f(x)=x^2

g(x)=\left(\dfrac{1}{3}x\right)^2

To find:

The statement that best compares the graph of g(x) with the graph of f(x).

Solution:

The horizontal stretch is defined as:

g(x)=f(kx)            ...(i)

If 0, the function f(x) is horizontally stretched by factor \dfrac{1}{k}.

If k>1, the function f(x) is horizontally compressed by factor \dfrac{1}{k}.

We have,

f(x)=x^2

g(x)=\left(\dfrac{1}{3}x\right)^2

Using these functions, we get

g(x)=f\left(\dfrac{1}{3}x\right)         ...(ii)

On comparing (i) and (ii), we get

k=\dfrac{1}{3}

Since 0, the function f(x) is horizontally stretched by factor \dfrac{1}{\frac{1}{3}}=3.

Hence, the correct option is D.

5 0
3 years ago
Help need answer rn.
Marina CMI [18]

Answer:

The 3rd one

Step-by-step explanation:

8 0
3 years ago
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