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deff fn [24]
3 years ago
12

Can some one plzzz helps me with this

Mathematics
1 answer:
Sever21 [200]3 years ago
6 0
No a repeating decimals have number repeating such as 555555.
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Name a pair of vertical and adjacent angles in each figure. Find m<1
Grace [21]

Answer:

80 degrees

Step-by-step explanation:

Vertical angles are congruent, meaning that if a vertical angle is 80 degrees, the other vertical angle is 80 degrees; they have the same angle measure.

m < 1 = 80 degrees

3 0
2 years ago
Brody sliced a small pizza into 12 equal pieces. He ate ~ of the pizza. Which model represents three-fourths of twelve?
EastWind [94]

Answer:

Pie chart.

9 slices

Step-by-step explanation:

Three-fourths of twelve is written as

3/4 * 12

i.e 3/4 is multiplied by 12

multiplying 3 by 12 gives 36 and dividing it by 4 gives 9 .

So Brody ate 9 slices out of the 12 slices of pizza.

The graph used in circular shape is called the a pie chart.

If we draw a pie chart 3 of the 4 sections will be colored showing that he ate 3/4 of the pizza representing 9 slices out of 12.

Each slice can be represented separately.

8 0
3 years ago
Cedric had 2,204 baseball cards that he wanted to sell. He sold them in packages of 4 and charged $2.25 for each package. If he
anzhelika [568]
2,204/4 =551 packages
551x2.25=1,239.75$ is your final answer
3 0
3 years ago
israel started to solve a radical equation in this way: square root of x plus 6 − 4 = x square root of x plus 6 − 4 4 = x 4 squa
agasfer [191]

Lets solve our radical equation \sqrt{x+6}-4=x step by step.

Step 1 add 4 to both sides of the equation:

\sqrt{x+6} -4+4=x +4

\sqrt{x} +6=x+4

Step 2 square both sides of the equation:

\sqrt{x+6} =x+4

\sqrt{x+6}^2 =(x+4)^2

x+6=(x+4)^2

Step 3 expand the binomial in the right hand side:

x+6=x^2+8x+16

Step 4 simplify the expression:

0=x^2+8x-x+16-6

x^2+7x+10=0

Step 5 factor the expression:

(x+2)(x+5)=0

Step 6 solve for each factor:

x+2=0 or x+5=0

x=-2 or x=-5

Now we are going to check both solutions in the original equation to prove if they are valid:

For x=-2

\sqrt{x+6}-4=x

\sqrt{-2+6}-4=-2

\sqrt{4}-4=-2

2-4=-2

-2=-2

The solution x=2 is a valid solution of the rational equation \sqrt{x+6}-4=x.

For x=-5

\sqrt{x+6}-4=x

\sqrt{-5+6}-4=-5

\sqrt{1}-4=-5

1-4=-5

-3\neq -5

Since -3 is not equal to -5, the solution x=-5 is not a valid solution of the rational equation \sqrt{x+6}-4=x; therefore, x=-5 is an extraneous solution of the equation.

We can conclude that even all the algebraic procedures of Israel are correct, he did not check for extraneous solutions.

An extraneous solution of an equation is the solution that emerges from the algebraic process of solving the equation but is not a valid solution of the equation. Is worth pointing out that extraneous solutions are particularly frequent in rational equation.

8 0
3 years ago
Mae Ling earns a weekly salary of $380 plus a 5.0% commission on sales at a gift shop. How much would she make in a work week if
Margarita [4]

Calculate 5% of how much she sold, then add it to her weekly salary.


5% = 0.05

Commission: 4600 x 0.05 = $230


Total pay: 380 + 230 = $610

6 0
3 years ago
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