Answer:
The solution of the given inequality n < 5
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given inequality

<u><em>Step(i)</em></u>:-
Cross multiplication '4' we get
8 n - 12 < 4 ( n +2)
8 n - 12 < 4 n + 4×2
8 n - 12 < 4 n +8
Subtracting '4 n ' on both sides, we get
8 n - 4 n - 12 < 4 n - 4 n +8
4 n - 12 < 8
<u><em>Step(ii):-</em></u>
Adding ' 12 ' on both sides , we get
4 n -12 + 12 < 8 + 12
4 n < 20
Dividing "4' on both sides , we get
n < 5
The solution is n < 5
<u><em>Conclusion:-</em></u>
The solution of the given inequality n < 5
Answer:

Step-by-step explanation:
T is a linear transformation, hence it is homogeneous (T(cr)=cT(r) for all real c and r∈ℝ³) and additive (T(r+s)=T(r)+T(s), for all r,s∈ℝ³). Apply these properties with r=3u and s=2v to obtain:

We don't have an explicit definition of T, so it's more difficult to compute T(3u+2v) directly without using these properties.
Please, share just ONE problem at a time. Thanks.
<span>Solve 2x^2-12x+20=0:
Simplify this by dividing each term by 2: x^2 - 6x + 10 = 0
Identify a, b and c: a=1, b=-6 and c=10. Then b^2=36.
Write out the solutions using the quadratic formula:
6 plus or minus sqrt(36-40)
x = ---------------------------------------
2
sqrt(36-40) = sqrt(-4) = plus or minus i2
Then:
6 plus or minus i2
x = --------------------------- (answer)
2</span>
Answer:
Domain: 1 ≤ x ≤ 4
Range : 1 ≤ f(x) ≤ 4
Step-by-step explanation:
The domain of a function f(x) is the limit within which the values of x varies.
Here, in the graph, it shows that the maximum value of x is 4 and the minimum value of x is 1.
Therefore, the domain of the function is 1 ≤ x ≤ 4
Again the range of a function f(x) is the limit within which the values of f(x) vary.
Here, the graph shows that the maximum value of f(x) is 4 and the minimum value of f(x) is 1.
Therefore, the range of the function f(x) is 1 ≤ f(x) ≤ 4. (Answer)