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lubasha [3.4K]
4 years ago
5

Pls help ASAP I need it for tomarrow

Mathematics
1 answer:
kozerog [31]4 years ago
8 0

Answer:

The answer is 140 cars .

Step-by-step explanation:

\frac{1}{5} × 300 = 60

\frac{1}{3} × 300 = 100

100 + 60 = 160

300 - 160 = 140

TEXT:

One-fifth of 300 is 60.  One-third of 300 is 100.  If you add both vintage and race cars you get 160.  the total, 300, minus the vintage and race cars, 160, is 140 cars.  

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What is the retail price of something that cost $280 with a 75% mark up?
IgorLugansk [536]

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The thumb length of fully grown females of a certain type of frog is normally distributed with a mean of 8.59 mm and a standard
PilotLPTM [1.2K]

Answer:

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 8.59, \sigma = 0.63

Calculate the probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

This is 1 subtracted by the pvalue of Z when X = 9.08. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.08 - 8.59}{0.63}

Z = 0.78

Z = 0.78 has a pvalue of 0.7823

1 - 0.7823 = 0.2177

21.77% probability that a randomly selected frog of this type has thumb length longer than 9.08 mm.

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12 square + 9 square= c square
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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