1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Brut [27]
3 years ago
15

Which age group is most likely to experience stage

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
8 0

The most prevalent age group reporting stage fright was between 35 and 45 years of age. Wind instrument players were the group most involved (22% of those reporting stage fright).

weqwewe [10]3 years ago
5 0
13-19 now days lol but low key 20-30 probably
You might be interested in
WOULD YOU RATHER receive 40% off 15 copies OR 50% of 25 copies?
valentinak56 [21]

Answer:

hahaha

Step-by-step explanation:

hahahahahayou dont know d answer hahaha but i know its a secret

8 0
3 years ago
Read 2 more answers
A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri
GuDViN [60]

Answer:

1.\frac{dy}{dt}=ky

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

\frac{dy}{dt}=Number of bacteria per unit time

\frac{dy}{dt}\proportional y

\frac{dy}{dt}=ky

Where k=Proportionality constant

2.\frac{dy}{y}=kdt,y'(0)=100

Integrating on both sides then, we get

lny=kt+C

We have y(0)=200

Substitute the values then , we get

ln 200=k(0)+C

C=ln 200

Substitute the value of C then we get

ln y=kt+ln 200

ln y-ln200=kt

ln\frac{y}{200}=kt

\frac{y}{200}=e^{kt}

y=200e^{kt}

Differentiate w.r.t

y'=200ke^{kt}

Substitute the given condition then, we get

100=200ke^{0}=200 \;because \;e^0=1

k=\frac{100}{200}=\frac{1}{2}

y=200e^{\frac{t}{2}}

Substitute t=2

Then, we get y=200e^{\frac{2}{2}}=200e

y=200(2.718)=543.6=543.6

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0
4 years ago
How to find x and y I dont understand
lesantik [10]
68= 4x-2+30 (notice they are vertical angles)
68= 4x+28
40=4x
10=x

68+y= 180 (forms a straight angle)
y=112

Final answer: x=10, y=112
4 0
3 years ago
Read 2 more answers
If two angles are complementary then both angles must be acute true or false
Oxana [17]

Answer:

If two angles are acute angles, then they are complementary. Incorrect. The converse is “If two angles are complementary, then they are acute angles” which is true and the original statement was false because two acute angles are not always complementary.

Step-by-step explanation:

7 0
3 years ago
EXPERT ONLY HELP: I'LL GIVE BRAINLIEST: EXPLAIN YOU ANSWER<br> A or C
RideAnS [48]

Answer:

Its A : 1188

Step-by-step explanation:

Because you have two heights 5 and 6 so add them together

5+6 = 11

then to get the volume you have to multiply length (9) , height (11), and width (12) to get the answer so..

11 x 12 x 9=1188

5 0
3 years ago
Read 2 more answers
Other questions:
  • What additional information would you need to prove that triangle ABC is congruent to triangle DEF by ASA
    9·1 answer
  • What is the sum of all the angles in a triangle
    5·1 answer
  • Write the inequality for this graph.<br> Use x as your variable.<br> (Zoom in for better quality)
    5·2 answers
  • In mr. sneed's classroom, there are 132 tiles and 11 lights. what is the ratio of lights to tiles in mr. sneed's classroom?
    8·1 answer
  • Solve by the square root method 2b^2=96<br>(^2=squared)
    6·1 answer
  • The population density of a city is 1,148 persons per square mile.
    13·2 answers
  • What’s the slope of the line?
    14·1 answer
  • In ΔBCD, the measure of ∠D=90°, BD = 20, CB = 29, and DC = 21. What is the value of the cosine of ∠C to the nearest hundredth?
    9·1 answer
  • The ratio of boys to girls in chorus is 2:5. If there are 42 students in the chorus how many are boys
    7·2 answers
  • 1. A line passes through the point (2, k) and (4k, 5) and has a slope of 1/2 . Find the value of k.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!