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fgiga [73]
3 years ago
15

What is the perimeter of the figure ( 50in 10in 40in 18in )

Mathematics
2 answers:
Nady [450]3 years ago
8 0
The perimeter is given by adding up all the side lengths; we are given all but two of the lengths, which we must calculate:

(1) The unknown side length that joins that which is 18 in. would be equal to 50 - 10 = 40 in.
(2) The unknown side length that joins that which is 10 in. would be equal to 40 - 18 = 22 in.

Thus the perimeter would be equal to:
50 + 40 + 10 + 18 + 40 + 22
= 180 in.
Alja [10]3 years ago
5 0
50 + 18 + (50 - 10) + (40 - 18) + 10 + 40 = 180
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Answer:

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Step-by-step explanation:

Given

5 tuples implies that:

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Required

How many 5-tuples of integers (h, i, j, k,m) are there such thatn\ge h\ge i\ge j\ge k\ge m\ge 1

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Also considering that repetition is allowed:  This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

^{n}C_r => ^{n + 4}C_5

^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}

^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}

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^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}

^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}

<u><em>Solved</em></u>

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