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andreyandreev [35.5K]
3 years ago
12

Someone please solve all equations

Mathematics
1 answer:
Tamiku [17]3 years ago
3 0

17. (a) The formula with CP subject is CP=\frac{SP}{1.1}

(b) The Cost Price of item without GST is $59.50

(c) The GST of item is $5.95

Step-by-step explanation:

Given formula is;

SP = 1.1 * CP

SP = Selling price

CP = Cost price

(a) Rearrange the formula to make CP the subject;

SP = 1.1 * CP

Dividing both sides by 1.1

\frac{SP}{1.1}=\frac{1.1*CP}{1.1}\\\\\frac{SP}{1.1}=CP\\\\CP=\frac{SP}{1.1}

The formula with CP subject is CP=\frac{SP}{1.1}

(b) Use your formula from (a) to find the Cost Price of an item without GST if the selling price is $65.45

SP = $65.45

CP=\frac{65.45}{1.1}\\\\CP=\$59.50

The Cost Price of item without GST is $59.50

(c) Calculate the amount of GST on an item whose selling price is $65.45.

GST = 10% of CP

GST = \frac{10}{100}*CP

GST = 0.1CP

From part (b)

CP = $59.50

GST = 0.1 * 59.50

GST = $5.95

The GST of item is $5.95

Keywords: percentage, multiplication

Learn more about multiplication at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

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Help! answer options included
lawyer [7]

Answer:

Y = [-6  6 6 -6]

Step-by-step explanation:

From the given matrices

If X - 2Y  = Z

b - 2c = a ... 1

a -2d = c ...2

4+2a = 16.... 3

a + 2b = b .... 4

From3 ;

2a = 16-4

2a = 12

a = 6

From 4;

a + 2b - b = 0

a+b = 0

a = -b

6 = -b

b  = -6

From1;

b - 2c = a

-6 - 2c = 6

-2c = 12

c = -6

also

a - 2d = c

6-2d = -6

-2d = -6-6

-2d = -12

d = 6

Hence the matrices Y = [-6  6 6 -6]

4 0
2 years ago
Solve for x. <br><br>x/4 = -1​
Lyrx [107]

Answer: -4

Step-by-step explanation: -4/4 = -1

Please mark Brainliest!

8 0
3 years ago
Read 2 more answers
Someone help me out here.
Vladimir [108]
Cremini:
$11.25 for 2/3 lb
2/3 lb = $11.25
1 lb = 11.25 ÷ 2/3 = $16.88 (nearest cent)

Chanterelle:
$7.99 for 1/2 lb
1/2 lb = $7.99
1 lb = $7.99 x 2 = $15.98

Answer:  Chanterelle costs less. It costs $0.90 less than Cremini.

4 0
3 years ago
(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
Evgesh-ka [11]

Answer:

(1)

Multiplying by 3 both sides of the equality you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

3u  is in the Span of the vectors \{v_1,v_2,v_3\}.

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

Step-by-step explanation:

(1)

As the hint indicates, you know that

u = c_1 v_1 + c_2v_2+c_3v_3

Then, if you multiply both sides of the equality by 3, you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

And that's it. 3u  is in the Span of the vectors \{v_1,v_2,v_3\}

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

4 0
3 years ago
If f(x)=2x-4and g(x)=x^2 what is f(g(x))
DerKrebs [107]
F(g(x))
sub g(x) for every x in f(x)

f(g(x))=2(g(x))-4
f(x^2)=2(x²)-4
f(g(x))=2x²-4
7 0
3 years ago
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