Someone please solve all equations
1 answer:
17. (a) The formula with CP subject is
(b) The Cost Price of item without GST is $59.50
(c) The GST of item is $5.95
Step-by-step explanation:
Given formula is;
SP = 1.1 * CP
SP = Selling price
CP = Cost price
(a) Rearrange the formula to make CP the subject;
SP = 1.1 * CP
Dividing both sides by 1.1
The formula with CP subject is
(b) Use your formula from (a) to find the Cost Price of an item without GST if the selling price is $65.45
SP = $65.45
The Cost Price of item without GST is $59.50
(c) Calculate the amount of GST on an item whose selling price is $65.45.
GST = 10% of CP
GST =
GST = 0.1CP
From part (b)
CP = $59.50
GST = 0.1 * 59.50
GST = $5.95
The GST of item is $5.95
Keywords: percentage, multiplication
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Hello,
Let's assume k the ratio.
Let's assume k the ratio.
The cost of pen and pencils are related to the number that can be bought
with a given amount of money.
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Reasons:
The given parameters are;
If the number number of pens and pencils James buys = 3 pens and 2 pencils, the amount James will have left = $2
If the number of pens and pencils James buys = 2 pens and 3 pencils, the amount James will have left = $6
The amount of money Judith has = The amount of money with James
The number of pens and pencil James and Judith can buy = 6 pens and 6 pencils
The cost of one pen = a
The cost of one pencil = b
Required:
To find the ordered pair (a, b)
Solution:
Let <em>X</em> represent the initial amount of money James has, we get;
X - (3·a + 2·b) = 2...(1)
X - (2·a + 3·b) = 6...(2)
2·X = 6·a + 6·b...(3)
Therefore;
X = (6·a + 6·b) ÷ 2 = 3·a + 3·b
Which from equation (1) gives;
3·a + 3·b - (3·a + 2·b) = 2
3·a + 3·b - 3·a - 2·b = 2
3·b - 2·b = 2
b = 2
Subtracting equation (1) from equation (2) gives;
(X - (2·a + 3·b)) - (X - (3·a + 2·b)) = 6 - 2 = 4
-2·a - 3·b + 3·a + 2·b = 4
a - b = 4
a = 4 + b
∴ a = 4 + 2 = 6
a = 6
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