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4 years ago

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A box contains ten cards labeled J, K, L, M, N, O, P, Q, R, and S. One card will be randomly chosen. What is the probability of

choosing a letter from L to Q?

1 answer:

vovikov84 [41]4 years ago

8 0

There are 10 cards and you are looking to find the probability of choosing 1 of 6 cards. so essentially 6/10 or 3/5 which are both equivalent to 60%

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46) write the expression: The quotient of p and q is twelve less than three times the sum of P and q

katovenus [111]

Answer:

Step-by-step explanation:

p/q = 3(p + q) - 12

The quotient of p and q: p/q quotient means division

is means =

3(p + q) is three times the sum of p and q

3(p + q) - 12 twelve less than three times the sum of p + q

6 0

3 years ago

What is the slope of the line that passes through the points e(-1,4) and f(2,6)?

Marysya12 [62]

(-1,4)(2,6)
slope = (6 - 4) / (2 - (-1) = 2 / (2 + 1) = 2/3 <==

4 0

3 years ago

Laila wants to create a data display to clearly show the median salary, the highest salary,

deff fn [24]

Answer:

a box plot

Step-by-step explanation:

Given the number of employees at her company is 685

If she chooses to create a dot plot, it means that she need to draw a lot, the total number of dots is 685 and even a wide domain of the number of data values on the x-axis.

If she chooses the box lot, which means that she wants to displays the five-number summary of a set of data. The five-number summary is the minimum, first quartile, median, third quartile, and maximum.

=> So it is the best fit for her choice.

If she chooses histogram, it means that she wants to group numbers into ranges to identify the underlying frequency distribution (shape) of a set of continuous data

Hope it will find you well

7 0

3 years ago

Read 2 more answers

What is the third angle of a right triangle if one of the angles measures 51.

Elodia [21]

Answer:

39

Step-by-step explanation:

The short answer is 39.

Every triangle has 180 degrees. There are no exceptions to this rule.

Since a triangle has 3 angles, all three together must add up to 180o

A right angle = 90 degrees always.

You are given 51 degrees as your second angle

The third one is x

x + 51 + 90 = 180 Total of three angles must be 180

x + 141 = 180 The left has been added to give 141

x = 180 - 141 Subtract 141 from both sides

x = 39 The third angle = 39

3 0

3 years ago

Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t

Svet_ta [14]

Answer:

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

$T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}$

$[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

$T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}$

$[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]$

Finally, the third vector of basis E is $e3(t)=t^{2}$

$T[e3(t)]=T(t^{2})$

in the equation : a2 = 1

$T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}$

Then

$[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]$

And that is the third column of [T]EE

Let's write our matrix

$[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]$

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

$X=\left[\begin{array}{c}1&0&0\\\end{array}\right]$

$AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]$

Applying the coordinates 2,6 and -2 to the basis E we obtain

$2+6t-2t^{2}$

That was the original result of T[e1(t)]

8 0

3 years ago