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nasty-shy [4]
3 years ago
15

I need to know the answer, workout, and explanation of this problem

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

20/ 18 = 1.11111

90/2.5 = 36

20/1.5 = 1.33333333

3 2/3 (3.666)/ 15 = 0.2444

So the answer is B


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HELP ! MARKING BRAINLEST TO WORK THIS OUT
natulia [17]

Answer:

16% = 73.6

Step-by-step explanation:

If 1% is = 4.6 then 16% is

1* 16 % = 4.6 * 16

16% = 73.6

8 0
3 years ago
Brass is made up of copper and zinc. 100 grams of brass contains 20 grams of zinc.
Nana76 [90]

Answer:

A.  12 grams Zn

B.  280 g of copper.

Step-by-step explanation:

100 grams of brass

20 grams of zinc

100 grams of brass has 20 grams of Zn.

20/100 = 0.200  Zn   <u>20% Zn  and 80% copper</u>.

A.  (60 g brass)*(0.2) = 12 grams Zn

B.  (350 g brass)*(0.80) = 280 g of copper.

5 0
2 years ago
Find the Laplace transformation of each of the following functions. In each case, specify the values of s for which the integral
MAVERICK [17]

Answer:

a. \frac {2} {s-1} converges to s> 1.

b. \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. - \frac {2}{s + 3} converges to s> - 3.

d. \frac {s}{s^2 + 25} converges to s> 0.

e. \frac {10} {s^2 + 1} converges even s> 0.

f. \frac {12}{s^2 + 4} converges to s> 0.

g. -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. \frac {1} {s ^ 2 + 4} converges to s> 0.

Step-by-step explanation:

a. L \left\{2e^t \right\} = 2L \left\{e^t \right\} = 2 \cdot \frac {1} {s-1} = \frac {2} {s-1} converges to s> 1.

b. L \left\{3e^{5t-3} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = 3e^{-3} L \left\{e^{5t} \right\} = \frac{3}{e^3 \left(s-5 \right)} converges to s> 5.

c. L \left\{-2e^{-3t} \right\} = -2L \left\{e^{-3t} \right\} = - \frac {2}{s + 3} converges to s> - 3.

d. L \left\{\cos\left (5t \right)\right\} = \frac {s}{s^2 + 25} converges to s> 0.

e. L \left\{10 \sin\left(t\right)\right\} = 10L\left\{\sin\left(t\right)\right\} = \frac {10} {s^2 + 1} converges even s> 0.

f. L \left\{6\sin \left(2t \right) \right\} = 6L\left\{\sin\left (2t\right)\right\} = \frac {12}{s^2 + 4} converges to s> 0.

g. L \left\{-5\cos\left(2t + 1\right) \right\} = -5L\left\{\cos\left(2t + 1 \right)\right\} = -\frac {5\left(\cos\left (1\right) s-2 \sin\left(1\right)\right)}{s^2 + 4} converges to s> 0.

h. L\left\{\sin \left(t\right)\cos \left(t\right)\right\} = L\left\{\sin\left(2t\right)\frac{1}{2}\right\} =\frac{1}{2}\cdot \frac{2}{s^2+4} = \frac {1} {s ^ 2 + 4} converges to s> 0.

7 0
3 years ago
PLS SOMEONE HELP ME ASAP
babymother [125]

Answer:

A. (2i)(8) = d. 16i

B. 16i³ = b. -16i

C. (2i)⁴ = a. 16

D. (2i)(8i) = c. -16

Step-by-step explanation:

A. Multiply 2i by 8 to get 16i, which corresponds to d.

B. The exponent is 3 more than a mulitple of 4 in 16i³, so the answer is negative. -16i corresponds to b.

C. (2i)⁴ has an exponent that is a multiple of 4, so the i isn't needed. 16 corresponds to a.

D. (2i)(8i) simplifies to 2(8) * i². The exponent is 2 more than a multiple of 4, so the answer is negative, without an i. -16 corresponds to c.

8 0
3 years ago
Aquestion that can be answered by<br> collecting data that has variability,
riadik2000 [5.3K]

You need to give more info

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