Question

When Joey mowed lawns for 10 hours and walked dogo

Answer 1

The charges for mowing lawns are $5 per hour and charges for walking dogs are $3 per hour.

Step-by-step explanation:

Let,

x be the charge per hour for mowing lawns

y be the charge per hour for walking dogs

According to given statement;

10x+4y=62    Eqn 1

8x+5y=55      Eqn 2

Multiplying Eqn 1 by 5

$5(10x+4y=62)\\50x+20y=310\ \ \ Eqn\ 3$

Multiplying Eqn 2 by 4

$4(8x+5y=55)\\32x+20y=220\ \ \ Eqn\ 4$

Subtracting Eqn 4 from Eqn 3

$(50x+20y)-(32x+20y)=310-220\\50x+20y-32x-20y=90\\18x=90$

Dividing both sides by 18

$\frac{18x}{18}=\frac{90}{18}\\x=5$

Putting in Eqn 1

$10(5)+4y=62\\50+4y=62\\4y=62-50\\4y=12$

Dividing both sides by 4

$\frac{4y}{4}=\frac{12}{4}\\y=3$

The charges for mowing lawns are $5 per hour and charges for walking dogs are $3 per hour.

Keywords: linear equation, subtraction

Learn more about linear equations at:

• brainly.com/question/2821386
• brainly.com/question/2860697

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