3 years ago

Henry correctly subtracted 3p+5/3p from p+3/p-2 and got 12p^2+9p-3p^2+p+10/(p-2)(3p). What is the simplified difference?

Mathematics

1 answer:

IrinaK [193]3 years ago

8 0

Answer:

Step-by-step explanation:

Henry subtracted ( 3p+5)/3p from ( $(\frac{p+3}{p-2})$ and got

$\frac{(12p^{2}+9p-3p^{2}+p+10}{(p-2)(3p)}$

We have simplify the difference

= $\frac{(12p^{2}+9p-3p^{2}+p+10}{(p-2)(3p)}$ = $\frac{(12p^{2}-3p^{2})+(9p+p)+10}{(p-2)(3p)}$

= $\frac{9p^{2}+10p+10}{(p-2)(3p)}$

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