U autocorrect this as thsi too!? Omg
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
Answer:
D
Step-by-step explanation:
Interesting question. The wording is a bit awkward. I think you have to assume the base is a square and each succeeding base is also a square.
So the first thing to do is to add the bases together.
30*30 + 23*23 + 16*16 + 9*9
Don't add these -- not yet.
Now take the height into consideration
6 *(30*30 + 23*23 + 16*16 + 9*9)
The point is that you only have to multiply by 6 once.
6*(900 + 529 + 256 + 81)
6*(1766)
10596 cubic inches
The answer is D
It is option c. Because when we substitute x for -1 we get the remainder as 1.
