Which one the first three???
Answer:
Step-by-step explanation:
It asks for the common set of A and B.
<u>There only one element common to both the given sets:</u>
- A={2,3,5,7} and B={2,4,6,8} ⇒ A∩B = {2}
Answer:
104
Step-by-step explanation:
tan(60) = opposite/adjacent
tan(60) = X/60
X = 60×tan(60)
X = 103.9230484541
X = 104 (3 sf)
Answer:
Option D is correct.
Step-by-step explanation:
We need to find the pattern in the values as the exponents increase.
First value is 1/3
if we multiply 3 with 1/3 i.e. 1/3*3 we get 1
The next value is 1 in the table.
Now, if we multiply 1 with 3 i.e. 1*3 we get 3
The next value is 3 in the table.
Now, if we multiply 3 with 3 i.e 3*3 we get 9
So, the next value is 9 in the table.
So, if we multiply 3 with the previous value we get the next value in the table.
Hence Option D multiply the previous value by 3 is correct.
The pile contains 17 quarters and 15 half-dollars.
Let <em>x</em> = the number of quarters and <em>y</em> = the number of half-dollars.
We have two equations:
(1) $0.25<em>x</em> + $0.50<em>y</em> = $11.75
(2) <em>x</em> = <em>y</em> +2
Substitute the value of <em>x</em> from Equation (2) into Equation (1).
0.25(<em>y</em>+2) + 0.50<em>y</em> = 11.75
0.25<em>y</em> + 0.50 + 0.50<em>y</em> = 11.75
0.75<em>y</em> = 11.75 – 0.50 = 11.25
<em>y</em> = 11.25/0.75 = 15
Substitute the value of <em>y</em> in Equation (2).
<em>x</em> = 15 + 2 = 17
The pile contains 17 quarters and 15 half-dollars.
<em>Check</em>: 17×$0.25 + 15×$0.50 = $4.25 + $7.50 = $11.75.
