Answer:
y=2x-2
Step-by-step explanation:
<em>the slope is y/x</em>
the slope is 2 or 2/1
<em>subtract 2 from the y value and 1 from the x value</em>
(3-1,4-2) = (2,2)
<em>keep doing this until you get a 0 in the x value</em>
(2-1,2-2) = (1,0)
<em>1 is your x-intercept</em>
(1-1,0-2) = (0,-2)
-2 is your y intercept.
So now you know your y-intercept and your slope so you can now write your equation.
<em>y=mx+b</em>
<em>m=slope, b=y-intercept</em>
m=2, b=-2
<em>substitute into the equation</em>
y=2x-2
The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
Answer: y = 
Step-by-step explanation:
x+6y=12
6y=-x+12
y=-
+ 2
If its parallel it means that the slope will be the same
y = mx + b
-4 = -1/6 * (-6) + b
b = -5
Thus,
y = -1/6 x - 5
The quotient of a number and 15
When you are given a point (x1,y1) and slope m the equation is
y-y1=m(x-x1)
given
slope=7
(x,y)
(3,22)
x1=3
y1=22
y-22=7(x-3) is the equation or
y=7x+1
