Let’s first see the probability of landing an even number. We have 6 sides, and 3 are labeled with an even number. So our chances of rolling a number cube are 3/6 (or 1/2 when simplified).
Next, the probability of rolling a number less then five is 4/6 (or 2/3 simplified), since we have 4 sides labeled with a number less than 5.
To compute two or more probabilities, we multiply them. In this case, the fractions already share the same denominator, 6 (because it’s a cube with 6 sides). So we get:
3/6 * 4/6
We then square 6, which is 36, and multiply 3 by 4, which is 12. This gives us 12/36, which is 1/3 in simplified form.
So there’s out answer: 1/3.
Macro can finish the puzzle in 3 hours. We can say that her speed for working is 1/3 or 1/3 puzzle per hour.
Now if they work together, this turns into 1 puzzle per hour.
That must mean that Cliff would be doing the other 2/3 of the puzzle while Macro does his 1/3 in that hour. If Cliff has a speed of doing them 2/3 per hour. Then it would take 1 and a half hour to finish 1 whole puzzle.
<span>D) perpendicular bisector <em>I believe.
</em></span>
Answer:
The conclusion "T" logically follows from the premises given and the argument is valid
Step-by-step explanation:
Let us use notations to represent the steps
P: I take a bus
Q: I take the subway
R: I will be late for my appointment
S: I take a taxi
T: I will be broke
The given statement in symbolic form can be written as,
(P V Q) → R
S → (¬R ∧ T)
(¬Q ∧ ¬P) → S
¬R
___________________
∴ T
PROOF:
1. (¬Q ∧ ¬P) → S Premise
2. S → (¬R ∧ T) Premise
3. (¬Q ∧ ¬P) → (¬R ∧ T) (1), (2), Chain Rule
4. ¬(P ∨ Q) → (¬R ∧ T) (3), DeMorgan's law
5. (P ∨ Q) → R Premise
6. ¬R Premise
7. ¬(P ∨ Q) (5), (6), Modus Tollen's rule
8. ¬R ∧ T (4), (7), Modus Ponen's rule
9. T (8), Rule of Conjunction
Therefore the conclusion "T" logically follows from the given premises and the argument is valid.
