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Rus_ich [418]
3 years ago
7

Find the equation of a line with a slope of −2 and a​ y-intercept of ​(0,o).

Mathematics
1 answer:
kari74 [83]3 years ago
6 0
The equation should be y=-2x .
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Convert 12,5% to a decimal fraction.
Stolb23 [73]
Decimal fractions don't exist. Do you mean convert to a decimal and a fraction?
5 0
3 years ago
By solving substitution y=4x-6<br> Y= 5x how I need steps
stiv31 [10]

Answer:

x= -6

Step-by-step explanation:

y=4x-6

y=5x, so where ever you see y, put 5x there.

hence, 5x=4x-6

5x-4x=-6

x= -6

5 0
3 years ago
13x=-21-6y and -8x=36+6y
IgorLugansk [536]

Answer:

x=3\\y=-10

Step-by-step explanation:

13x=-21-6y\\-8x=36+6y

Let's take one of the equations and solve for x. I'll take the first one.

13x=-21-6y

Divide by 13.

x=\frac{-21-6y}{13}

Now replace x in the second equation.

-8x=36+6y\\-8(\frac{-21-6y}{13} )=36+6y

Distribute -8

\frac{168+48y}{13}=36+6y

Break down the fraction.

\frac{168}{13}+\frac{48}{13}y=36+6y

Subtract \frac{168}{13}

\frac{48}{13}y=36+6y-\frac{168}{13}

Subtract 6y

\frac{48}{13}y-6y=36-\frac{168}{13}

Combine like terms;

\frac{48-13*6}{13}y=\frac{36*13-168}{13}

Solve;

\frac{48-78}{13}y=\frac{468-168}{13}

Keep solving;

\frac{-30}{13}y=\frac{300}{13}

Multiply by the negative reciprocal of the fraction next to y.

(-\frac{13}{30} )\frac{-30}{13}y=\frac{300}{13}(-\frac{13}{30} )

On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10

y=-10

After having found y, replace it in any of the equations to find x.

13x=-21-6y\\13x=-21-6(-10)\\13x=-21+60\\13x=39\\x=\frac{39}{13}\\ x=3

6 0
3 years ago
Read 2 more answers
Which sentence explian why the slope of AB is equal to the slope BC ?
slava [35]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Select from the drop-down menu to correctly compare the numbers.
OverLord2011 [107]
This questions can be answered with a calculator, but I have an impression it is meant to be a mental calculation problem, which can be solved as follows.

We know that 10*10=100, in otherwords, &radic; 100 = 10 which is greater than 9.4247.

We also know that &radic; 108  is greater than &radic; 100 =10

So we can conclude that
&radic; 108 > &radic; 100 = 10  > 9.4247
or simply

&radic; 108 > 9.4247

by the transitive property of logical propositions.


6 0
3 years ago
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