All categories

3 years ago

Find the GCF of the given polynomial. 16a4b4 + 32a3b5 - 48a2b6

Mathematics

1 answer:

Anna11 [10]3 years ago

6 0

16 $a^{4} b^{4} +32 a^{3} b^{5} -48 a^{2} b^{6}$
GCF=16 $a^{2} b^{4}$

You might be interested in

Why is 6 1/2 equal to the square root of 6

Aleksandr-060686 [28]

Because It Can Be Simplified Many Ways

4 0

3 years ago

Read 2 more answers

One of the sides of a rectangle has length 7. Which of the following points, paired with (6,5), will make a side of this length?

TiliK225 [7]

Answer:

B (6,12)

Step-by-step explanation:

The distance from point A (6,5) to point B should be 7.

A- (6,5)-> (7,5) is 1 unit right

B- (6,5)-> (6,12) is 7 units up

C- (6,5)-> (6,7) is 2 units up

D- (6,5)-> (12,5) is 6 units up

6 0

3 years ago

Hi. How are ya to day

Thepotemich [5.8K]

Answer:

good and what about you .

thanks 4 the 5 points . : )

4 0

3 years ago

What is the explicit rule for this geometric sequence? a1=-15;an=1/5•an-1

Ad libitum [116K]

Answer:

Option A is correct.

$a_n =-15 (\frac{1}{5})^{n-1}$

Step-by-step explanation:

Given: $a_1 = -15$ ; $a_n = \frac{1}{5} \cdot a_{n-1}$

for n = 2

$a_2 = \frac{1}{5} \cdot a_{2-1}$ = $\frac{1}{5}\cdot a_1 = \frac{1}{5} \cdot (-15)$

for n =3

$a_3 = \frac{1}{5} \cdot a_{3-1}$ = $\frac{1}{5} \cdota_2= (\frac{1}{5})^2\cdot (-15)$

Simlarly , for n =4

$a_3 = \frac{1}{5} \cdot a_{4-1}$ = $\frac{1}{5}\cdot a_3= (\frac{1}{5})^3\cdot (-15)$

and so on...

Common ratio(r) states that for a geometric sequence or geometric series, the common ratio is the ratio of a term to the previous term.

we have; $r = \frac{a_2}{a_1} = \frac{1}{5}$

Now; by recursive formula for geometric series:

$a_n = a_1 r^{n-1}$

where $a_1$ is the first term and r is the common ratio:

Substitute the value of $a_1 = -15$ and $r = \frac{1}{5}$

we have;

$a_n =-15 (\frac{1}{5})^{n-1}$

therefore, the explicit rule for the geometric sequence is; $a_n =-15 (\frac{1}{5})^{n-1}$

3 0

3 years ago

What is a equation of the line that is parallel to y=-5×+6 and passes through the point (-4,-1)

Alborosie

The equation of line parallel to y = -5x + 6 and passes through the point (-4, -1) is y = -5x -21

<h3><u>Solution:</u></h3>

Given that, a line passes through (-4, -1) and it is parallel to y = -5x + 6

We have to find the line equation of that line.

Now, as we can see given line equation is in slope intercept form y = mx + c

where "m" is the slope of line and "c" is the y-intercept

So, by comparison, slope of that line is m = -5

We know that slopes of two parallel lines are equal

And as the required line is parallel to given line, it will also have the same slope.

Then, slope of our line = -5

And let us find the line equation point slope form

y – a = m(x - b) where (b, a) is a point on the line

So, line equation is y – (-1) = -5(x – (-4))

y + 1 = -5(x + 4)

y + 1 = -5x – 20

y = -5x -20 – 1

y = -5x -21

Thus the equation of required line is y = -5x -21

5 0

3 years ago