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Hitman42 [59]
3 years ago
14

I forgot someone help me plz

Mathematics
2 answers:
baherus [9]3 years ago
8 0
1st Method:

(3² -2²) / (3-2)² = (9-4) / (1²)  = 5

2nd Method:

(3² -2²) / (3-2)² = (3-2)(3+2) / (3-2)², after simplification by (3-2), the remaining numerator = (3+2) n= 5

o-na [289]3 years ago
5 0
Write the conjugates of them then FOIL both the top and bottom, then factor

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Step-by-step explanation:

The only possibly way for 5 to multiply 2 numbers is if those numbers are in parenthesis

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Help me guys <br> thx so much
navik [9.2K]

Answer:

Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Step-by-step explanation:

<u>Step 1:  Multiply</u>

<u />(\sqrt{10x^4} -x\sqrt{5x^2} )*(2\sqrt{15x^4} + \sqrt{3x^3})\\ (\sqrt{10 * x^2 * x^2} -x\sqrt{5 * x^2} ) * (2\sqrt{15 * x^2 * x^2} +\sqrt{3 * x^2 * x})\\(x^2\sqrt{10} -x^2\sqrt{5} )*(2x^2\sqrt{15} +x\sqrt{3x}) \\\\

(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}

(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x}  )

2x^4\sqrt{5^2*6} + x^3\sqrt{30x} -2x^4\sqrt{5^2*3} -x^3\sqrt{15x}

10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

Answer:  Option D, 10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}

6 0
3 years ago
Read 2 more answers
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SpyIntel [72]

Answer:

0

Step-by-step explanation:

A horizontal line has a slope of zero and a vertical line has an undefined slope

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