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morpeh [17]
3 years ago
13

How much money should be deposited today in an account that earns 6% compounded monthly so that it will accumulate to $1000000 (

one million dollars) in 45 years?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

The principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

Step-by-step explanation:

Given

  • Accrued Amount A = $1000000
  • Interest rate r = 6% = 0.06
  • Time period t = 45 years
  • Compounded monthly n = 12

To determine:

  • Principle amount P = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

P\:=\frac{A}{\left(1\:+\:\frac{r}{n}\right)^{nt}}

substituting A = 1000000, r =  0.06, t = 45, and n = 12

P\:=\frac{1000000}{\left(1\:+\:\frac{0.06}{12}\right)^{12\cdot 45}}\:

    =\frac{1000000}{1.005^{540}}

P = 67659.17 $

Therefore, the principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

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Answer:

203

Step-by-step explanation:

17*7=119

12*7=84

84+119=203

4 0
2 years ago
Is this right or wrong ?
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Answer:

(3x - 2)(4x + 6) = 12 {x}^{2} + 18x - 8x + - 12 \\  = 12 {x}^{2} + 10x - 12

6 0
3 years ago
Which rate is the greatest?
faltersainse [42]

B, $432 per 24 hours

5 0
2 years ago
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There are 20 pieces of fruit in a bowl and 5 of them are apples. What percent of the fruit are apples?
Elodia [21]

Step-by-step explanation:

20fruits=100%

5fruits=?

5x100/20 5fruitsx5%

=24%

4 0
3 years ago
Sums of a sequence: How many total gifts did my true love give to me during the entire 12 days of Christmas? Hint: Without any o
ale4655 [162]
<span> On the first day of Christmas,
my true love sent to me
A partridge in a pear tree. On the second day of Christmas,
my true love sent to me
Two turtle doves,
And a partridge in a pear tree. On the third day of Christmas,
my true love sent to me
Three French hens,
Two turtle doves,
And a partridge in a pear tree. </span>

The song continues, adding 4 calling birds on the 4th day, 5 golden rings on the 5th, and so on up to the 12th day, when 12 drummers add to the cacophony of assorted birds, pipers and lords leaping all over the place.

Notice that on each day there is one partridge (so I will have 12 partridges by the 12th day), and each day from the second day onwards there are 2 doves (so I will have 22 doves), and from the 3rd there are 3 hens (total of 30 hens), and so on.

So, how many presents are there altogether?

Partridges: 1 × 12 = 12

Doves: 2 × 11 = 22

Hens 3 × 10 = 30

Calling birds: 4 × 9 = 36

Golden rings: 5 × 8 = 40

Geese: 6 × 7 = 42

Swans: 7 × 6 = 42

Maids: 8 × 5 = 40

Ladies: 9 × 4 = 36

Lords: 10 × 3 = 30

Pipers: 11 × 2 = 22

Drummers: 12 × 1 = 12

Total = 364

We observe that we have the same number of partridges as drummers (12 of each); doves and pipers (22 of each); hens and lords (30 of each) and so on. So the easiest way to count our presents is to add up to the middle of the list and then double the result: (12 + 22 + 30 + 36 + 40 + 42) × 2 = 364.


3 0
3 years ago
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