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Vilka [71]
4 years ago
11

Use any method to solve the equation. If necessary, round to the nearest hundredth. 7x2 − 16x = 8

Mathematics
2 answers:
mylen [45]4 years ago
8 0
Start with isolating the x
zaharov [31]4 years ago
3 0
7•2-16x=8
X= 3/8

I hope this helps.
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A survey was done where men and women were asked if they would prefer go to the beach or go to the mountains on vacation. The re
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A rectangular swimming pool measures 14 feet by 30 feet. The pool is
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step 1

Find the area of the path

The area of the path is equal to the area of the path plus the swimming pool minus the area of the swimming pool

A=(14+3+3)(30+3+3)-(14)(30)

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4 0
3 years ago
In this experiment researchers randomly assigned smokers to treatments. Of the 193 smokers taking a placebo, 29 stopped smoking
mezya [45]

Answer:

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

Step-by-step explanation:

To solve this question, we need to understand the Central Limit Theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard error is the square root of the sum of the variances:

Of the 193 smokers taking a placebo, 29 stopped smoking by the 8th day.

This means that:

p_S = \frac{29}{193} = 0.1503

s_S = \sqrt{\frac{0.1503*0.8497}{193}} = 0.0257

Of the 266 smokers taking only the antidepressant buproprion, 82 stopped smoking by the 8th day.

This means that:

p_A = \frac{82}{266} = 0.3083

s_A = \sqrt{\frac{0.3083*0.6917}{266}} = 0.0283

Calculate the estimated standard error for the sampling distribution of differences in sample proportions.

s = \sqrt{s_S^2 + s_A^2} = \sqrt{0.0257^2 + 0.0283^2} = 0.0382

The estimated standard error for the sampling distribution of differences in sample proportions is 0.0382.

7 0
3 years ago
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