Determine the equations of the vertical and horizontal asymptotes if any for f(x)=x/x-5
1 answer:
Answer:
Horizontal Asymptote: x = 0
Vertical Asymptote: x = 5
Step-by-step explanation:
The function is given as
<em>Horizontal asymptotes are found by equating numerator to 0 and solving for x</em>
<em>Vertical asymptotes are found by equating denominator to 0 and solving for x</em>
<em />
<u>Horizontal Asymptote:</u>
x = 0
<u>Vertical Asymptote:</u>
x - 5 = 0
x = 5
You might be interested in
I have to say something bc I am sleepy
You have to be a bit more specific than that
Answer:
Step-by-step explanation:
then the equation reads:
The standard form of an quadratic function is:
So the answer is:
Answer:
t cannot be -5 or 0 because these cause a 0 in the denominator and you cant divide by 0 that I'm aware of
What you're seeing here is 12 being multiplied by its reciprocal. 12 * 1/12 = 1. This is an example of a multiplicative inverse; a multiplicative inverse is when you multiply a number by its reciprocal (1 over the number).