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Ede4ka [16]
2 years ago
7

Scientific form of 47500000000​

Mathematics
2 answers:
Svetlanka [38]2 years ago
6 0

Hello There!

First, let's make sure our coefficient is between 1 and 10:

4.75

All numbers in scientific notation look like this:

___x10^- (some number)

4.75x10^

Now, the number is large, so the exponent is positive.

So we move the decimal place some number of units. We move the decimal place 10 units, so the exponent is 10:

4.75x10^10

Hope this helps!

~Just a felicitous girlie

#CarryOnLearning

SilentNature

melomori [17]2 years ago
5 0

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Scientific notation for above value is ~

  • 4.75 \times 10 {}^{10}

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How many different triangles can you make from 6 cm,6 cm, and 4 cm?
lubasha [3.4K]

Answer:

Step-by-step explanation:

The sides of a triangle are 6cm, 6cm, and 4cm.

According to triangle inequality, the sum of the length of any two sides of a triangle must be greater than the length of the third side.

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3 years ago
Please help. I will give five stars and 10 points for correct answer with explanation.
anygoal [31]

Answer:

A: It has no solution

Step-by-step explanation:

1. 3/4z - 1/4z + 3 = 2/4z + 5

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7 0
3 years ago
Two glasses of milk and 3 snack bars have a total of 61 carbohydrates​ (carbs), and 4 glasses of milk and 2 snack bars have a to
Sloan [31]

Answer:

24 carbohydrates

Step-by-step explanation:

Represent Snack bars with S and Milks with M.

So, we have:

2M\ and\ 3S\ = 61

and

4M\ and\ 2S\ = 70

Required: Solve for M and S

Convert the given expressions to mathematical expressions:

2M + 3S = 61 --- (1)

4M + 2S = 70 --- (2)

Multiply the first equation by 2

2M + 3S = 61 --------- * 2

4M + 6S = 122 --- (3)

Subtract (1) from (3)

4M - 4M + 6S - 2S = 122 - 70

4S = 52

Solve for S

S = 52/4

S = 13

Substitute 13 for S in (2)

4M + 2S = 70

4M + 2 * 13 = 70

4M + 26 = 70

Solve for 4M

4M = 70 - 26

4M = 44

Solve for M

M = 44/4

M = 11

1 glass of milk and 1 snack bar = S + M

S + M = 13 + 11

S + M = 24

6 0
3 years ago
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