All categories

3 years ago

Which ordered pair is a solution to the system of equations?

Mathematics

1 answer:

iren2701 [21]3 years ago

3 0

(- 2, - 3) is a solution to the given system of equations.

Answer: Option D

<u>Step-by-step explanation:</u>

Given equation are not presented in proper format. So, let assume the given system of are as below,

2 x - y = -1

2 x -4 y = 8

Now, subtract the second equation from the first, we get

(2 x - y) -(2 x - 4 y) = -1 -8

3 y = -9

y = -3 (obtained this when divide by 3)

Substituting y = - 3 into the first equation, we get

2 x - (-3) = - 1

2 x = - 1 + 3

x = - 2 (obtained when divide by 2)

Now, the answer is (x, y) = (- 2, - 3)

You might be interested in

He first term of a sequence is 2, and each subsequent term is the reciprocal of the square of the preceding term. what is the po

polet [3.4K]

The first term is a₁ = 2.
Each subsequent term is the reciprocal of the square of the preceding term.

2nd term:
a₂ = 1/2² = 1/4

3rd term:
a₃ = 1/(1/4)² = 1/(1/16) = 16

4th term:
a₄ = 1/16² = 1/256

5th term:
a₅ = 1/(1/256)² = 1/(1/65536) = 65536
The positive square root of the fifth term is
√(65536) = 256

Answer: 256

4 0

3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

3 years ago

What is the constant rate of change of (5,80) (4,64) and (6,96)

sveticcg [70]

Answer:

Step-by-step explanation:

The existence of the constant rate of change is given the ratio of y to x is the same. Then:

$k_{1} = \frac{80}{5}$

$k_{1} = 16$

$k_{2} = \frac{64}{4}$

$k_{2} = 16$

$k_{3} = \frac{96}{6}$

$k_{3} = 16$

In consequence, the constant rate of change is 16.

8 0

3 years ago

A small Business earns a profit of $6500 in January and $17,500 in May. What is the rate of change in profit for this time perio

lukranit [14]

Answer:
Rate of change of profit for this period = $2750 / month

4 0

3 years ago

The picture is attached with t

weeeeeb [17]

Your answers should be B and D

When naming angles, they all need to be connected on the line without overlapping any points previously said. Angle YXZ is incorrect because X is not on the same line as Z. YW is a line because both sides continue on forever, as indicated by the arrows.

Hope this helps!

6 0

3 years ago