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elena-14-01-66 [18.8K]
3 years ago
5

A chef at a restaurant uses pounds of butter each day. About how many grams of butter does the chef use each​ day? Use the conve

rsion factors and .
Mathematics
1 answer:
Vadim26 [7]3 years ago
7 0

Complete question :

A chef at a restaurant uses 12 pounds of butter each day. About how many grams of butter does the chef use each day? use the conversion factors 16 oz/1 lb and 28.35 grams/1oz

Answer:

5,424 grams

Step-by-step explanation:

To convert using the conversion factor :

Number of pounds of butter * (16 oz/1) * (28.35) /1

Hence,

12 * 16oz/ 1 * 28.35/1

(12 * 16 * 28)

= 5,424 grams

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Answer:

1 solution

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subtract 6 from both sides: -21x=3

Divide both sides by -21: x=-1/7

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2 years ago
An office uses 478 pounds of paper in one week. The paper comes in packages that hold 18 pounds of paper each. How many packages
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3 years ago
Third-degree, with zeros of −3 , − 2 , and 1 , and passes through the point ( 3 , 11 ) .
Masja [62]

Answer:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

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Lets   y  =  f(x)   in a cartesian coordinates

Having three zeros:

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That meas that if   x  takes the above mentioned  values " y " must be zero

therefore  y  must be of the form

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In that case for y to be zero one of the factors should be zero or

y  =  0        x  + 3 = 0    and  x = - 3  is a zero of the function y .

The same reasoning applies for the other two roots

Now we have to evaluate the other condition.

According to problem statement the function passes through the point ( 3, 11 ) , that means that when x =  3 ,  y have to be 11, therefore we plug in equation (1)  that value to see what happens

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )

11  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1)   =  6*5*2  = 60

Then we adjust the expression (1) to meet the condition of the function passing through point  ( 3 , 11) as:

y  =  ( 3 + 3 ) * ( 3 + 2 ) + ( 3 - 1) * 11/60    (2)

and check to see if we did right

for y to be zero      x   can be    x = - 3    x  =  -2   and  x = 1 in all these cases y = 0.  And if  x  =  3   in equation (2)  y = 11. And that what we want to shown. Then the solution is:

y  =   ( x + 3 ) *  ( x +  2 ) * ( x - 1 )* 11/60

8 0
3 years ago
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Nostrana [21]

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========================================================

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Let's plug in (x,y) = (-5,12), along with the slope m = 2, and solve for c

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Since m = 2 and c = 22, we go from y = mx+c to y = 2x+22

The equation of the parallel line is y = 2x+22

The graph is below.

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