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elena-14-01-66 [18.8K]
2 years ago
5

A chef at a restaurant uses pounds of butter each day. About how many grams of butter does the chef use each​ day? Use the conve

rsion factors and .
Mathematics
1 answer:
Vadim26 [7]2 years ago
7 0

Complete question :

A chef at a restaurant uses 12 pounds of butter each day. About how many grams of butter does the chef use each day? use the conversion factors 16 oz/1 lb and 28.35 grams/1oz

Answer:

5,424 grams

Step-by-step explanation:

To convert using the conversion factor :

Number of pounds of butter * (16 oz/1) * (28.35) /1

Hence,

12 * 16oz/ 1 * 28.35/1

(12 * 16 * 28)

= 5,424 grams

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You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O
Neko [114]

Answer:

a)q(p)=-15p+ +300

b)R(p)=-15p²+300p

c)C(p)=-30p+1600

d.1)P(p)=-15p²+330p-1600

d.2)p=$11

Step-by-step explanation:

(a).Before getting started, we are going to consider  the cartesian plane, where x-axis corresponds to the cover charge and y-axis corresponds to number of guests per night . There, we will locate the following coordinates according to the previous information:

(9,165)  (10,150).

Remember that  the slope-intercept form of the  linear equation is y=mx+b where m is the slope and b  is te intercept.

The slope can be calculated  by the next formula:

m=\frac{y2-y1}{x2-x1}

In this case we will assign  (9,165) as the first coordinate and (10,150) as the second one. The order does not matter. At the end we get the same value for m.

Therefore:

m=\frac{150-165}{10-9} = -15

Now, we have the slope and two poitns. According to this, and taking into account that  point-slope form of the equation of a line is y-y1=m(x-x1),   find a linear demand equation.

Any of two coordintates can be selected. In this case we will select the second one.

y-150=-15(x-10)   equation 1

Solve equation 1 for y

y=-15x+150+150

y=-15x+300

Above we had defined x as cover charge (p) and y as number of guests (q). Thus, rewrite equation 1.

q(p)=-15p+ +300.  

it equation shows the number of guests per night as a function of the cover charge,

(b). The nightly revenue can be calculated multplying the price of the cover charge by  the number of guests. So, we just have to multiply the equation 1 by p.

p*q(p)=p*(-15p +300)

R(p)=-15p²+300p   equation 2

(c) To get the cost function of the nightclub  we just have to multiply the cost of the two non-alcoholic drinks   by the number of the guests ( equation 1) and add to it  nightly overheads.

C(p)=2*(-15p+300)+1000

C(p)= -30p+600+1000

C(p)=-30p+1600  equation 3

(d) In order to find the profit in terms of the cover charge we will  subtract nightly costs ( equation 3) from nightly revenue (equation 2)

P(p)=R(p)-C(p)

P(p)=-15p²+300p - (-30p+1600)

P(p)=-15p²+300p+30p-1600

P(p)=-15p²+330p-1600

To determine that  the entrance fee we should charge for a maximum profit we are going to use the first derivative test (y'(x)=0) in order to find an extremum point.

Compute the first derivative of P(p)

P'(p)=-30p+330=0

30p=330

p=330/30

p= $11

The entrance fee that we should charge for a maximum profit is p=$11 per guest.

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3 years ago
Please help me with this
Soloha48 [4]

for an isosceles right triangle the legs would be 2 times the square root of the hypotenuse

 so for this:

the legs would be 2sqrt(10)


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3 years ago
Argyle has $1000 in his savings account. He wants to save more money. He is
Thepotemich [5.8K]
You would use the formula P(1+r/n)^nt=A I explained it in the picture and if the number is growing it is 1+r/n and if it’s not it is 1-r/n. Also if you don’t know the formula you can do it year by year which I also showed but it will take a long time and it’s easy to make a mistake. The answer would be A because if you plug the numbers into the formula you will get 4045.56 for plan b then you subtract 3000 and round, getting 1046. It is the formula of exponential growth/decay if you want to research further.

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3 years ago
Help with quadratic graphs asap!
zlopas [31]

x= -0.25 and 1.25

x = -0.5 and  1.5

x = 0 and 1

x = -0.375 and 1.625

Step-by-step explanation:

Given equation of the curve is

y = 4x^2 -4x-1

(i)

First equation 4x^2 -4x-1 =0

Here y = 0

In  x-axis the value of y = 0

The graph cuts the x-axis at(-0.25,0) and (1.25,0)

So, x= -0.25 and 1.25

(ii)

4x^2 -4x-1 =2

here y = 2

The line y= 2 cuts the curve at (-0.5,2) and (1.5,2)

So, x = -0.5 and  1.5

Given equation of the curve is

y= 3x^2-3x -1

(i)

3x^2-3x +2 =2

\Leftrightarrow  3x^2-3x -1 = -1

Here y = -1

The line y = -1  cuts the curve at (0,-1) and (1,-1)

So x = 0 and 1

(ii)

3x^2-3x -1 =x+1

Here y = x+1

The line y -x =1 cuts the curve at (-0.375,0.5) and (1.625,2).

So x = -0.375 and 1.625

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3 years ago
Identify the exponential function as a growth or decay function.
marusya05 [52]

Answer:

A

Step-by-step explanation:

A. growth

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2 years ago
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