Answer:
65625/4(x^5)(y²)
Step-by-step explanation:
Using binomial expansion
Formula: (n k) (a^k)(b ^(n-k))
Where (n k) represents n combination of k (nCk)
From the question k = 5 (i.e. 5th term)
n = 7 (power of expression)
a = 5x
b = -y/2
....................
Solving nCk
n = 7
k = 5
nCk = 7C5
= 7!/(5!2!) ------ Expand Expression
=7 * 6 * 5! /(5! * 2*1)
= 7*6/2
= 21 ------
.........................
Solving (a^k) (b^(n-k))
a = 5x
b = -y/2
k = 5
n = 7
Substituting these values in the expression
(5x)^5 * (-y/2)^(7-5)
= (3125x^5) * (-y/2)²
= 3125x^5 * y²/4
= (3125x^5)(y²)/4
------------------------------------
Multiplying the two expression above
21 * (3125x^5)(y²)/4
= 65625/4(x^5)(y²)
I think is
9 + x = 16 + 27
9 + x = 43
x = 52
The correct question is
The composite figure is made up of a triangular prism and a pyramid. The two solids have congruent bases. What is the volume of the composite figure<span>
?</span>
the complete question in the attached figure
we know that
[volume of a cone]=[area of the base]*h/3
[area of the base]=22*10/2-------> 110 units²
h=19.5 units
[volume of a cone]=[110]*19.5/3------> 715 units³
[volume of a triangular prism]=[area of the base]*h
[area of the base]=110 units²
h=25 units
[volume of a a triangular prism]=[110]*25------------> 2750 units³
[volume of a the composite figure]=[volume of a cone]+[volume of a <span>a triangular prism]
</span>[volume of a the composite figure]=[715]+[2750]-------> 3465 units³
the answer is
The volume of a the composite figure is 3465 units³
110x0.7= 77
110-77= 33
so 33 is your answer
<span>Its: 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23 </span>