18.70
Because they are 1.10 each
Answer:
Rectangle 1 area: 53 units squared
Shape 2 area: 43.75 units squared
Step-by-step explanation:
Shape 1:
We need to find the area of the two triangles in this rectangle and subtract it from the total area of the rectangle.
Total area of the rectangle:
13 * 5 = 65
Area of triangles (they are congruent):
1/2 * 4 * 3 = 6
6 * 2 = 12
65 - 12 = 53
The area of the shaded part is 53 (I don't know what your unit of measurement is. Just say units.)
Shape 2:
First, let's find the area of the parallelogram at the top.
10 * 3 = 30
Now, let's find the area of the rest of the shape. Triangle first...
1/2 * 4 * 1.5 = 3
Now, the rectangle and the tiny triangle we can section out at the end:
7 * 1.5 = 10.5 + 1/4 (Triangle) or 0.25 = 10.75
Total area: 10.75 + 3 + 30 = 43.75
Given:
The zeros of the polynomial are 
.
Degree = 4
Leading coefficient = 1
To find:
The polynomial.
Solution:
If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.
Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.
![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
Using distributive property, we get
On combining like terms, we get
Here, the leading coefficient is 1. So, it is the required polynomial.
Therefore, the correct option is E.
Answer:
the selected answer/2
Step-by-step explanation:
not a function because the same y has 2 different x values
Answer:
That would be B Collinear
