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Leokris [45]
3 years ago
11

If the radius of a circle equals 20 cm find its circumference correct to one decimal place

Mathematics
2 answers:
serg [7]3 years ago
8 0
The answer is 125.7 correct to one decimal place
Brums [2.3K]3 years ago
3 0

Answer:

125.66

Step-by-step explanation:

i don't get the one decimal place part but there your answer

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Kelly has a savings account with a beginning balance of $800.
hammer [34]

Answer:

Step-by-step explanation:

6 0
3 years ago
Otto invests $1,000 at age 20. Otto wants theinvestment to be worth $4,000 by age 30. Ifinterest is compounded continuously, wha
AveGali [126]
r\approx0.139

1) Since this is a Continuously Compounded operation in a 10 yrs period, then we can write out the following equation:

\begin{gathered} A=Pe^{rt} \\  \end{gathered}

2) Plugging into the equation the given data and since Otto is 20 yrs old and he plans to get $4,000 in ten years, we can write out:

\begin{gathered} 4000=1000e^{\mleft\{10r\mright\}} \\ \frac{4000}{1000}=\frac{1000e^{10r}}{1000} \\ 4=e^{10r} \\ \ln (4)=\ln (e)^{10r} \\ 10r=\ln (4) \\ r=\frac{\ln (4)}{10} \\ r=0.1386 \end{gathered}

3) Thus the rate Otto needs is

r=0.1386\approx0.139

Note that since the 0.1386 the six here is greater than 5 then we can round up to the next thousandth, in this case: 0.139. For the 0.1386 is closer to 0.139 (0.004) than to 0.138 (0.006).

Or 13.9%

8 0
1 year ago
O points
astraxan [27]

7.5 %

Step-by-step explanation:

We by finding how far from the mean the 999 volume caps are, using z score;

Z = (x – μ) / σ

Z = (999 – 998) / 7

Z = 0.143    

We use the z-table to find the confidence levels;

= 85%

= 0.85

Since we are finding proportion of bottles have volumes greater than 999

mL;

1 – .85 = .15

0.15/2 = 0.075

= 7.5%

5 0
3 years ago
Triangle LMN is located at L(2,3), M(1,2), and N(4,4). The triangle is then transformed using the rule (x+5, y+2) to form the im
charle [14.2K]
Using the rule (x+5, y+2) you would add 5 to the x value and 2 to the y value so the answer would be L' (7,5) M' (6,4) N' (9,6)
8 0
3 years ago
Can someone please give me the answers to this? ... please ...
Hoochie [10]

Step-by-step explanation:

come on ! based on all the other questions that have been answered AND explained you should be able to find these answers yourself now. what is still unclear ?

distance between 2 points (x1, y1) and (x2, y2):

Pythagoras : c² = a² + b²

c is the connection between the 2 points (and which length we need to find).

c = sqrt(a² + b²)

a and b are differences of the x coordinates and the differences of the y coordinates of these 2 points.

a = x1 - x2

b = y1 - y2

this is simply because, when you look at the coordinate grid, these 3 items make a right-angled triangle.

don't worry about any negative values for a and b, as the square eliminates the negative sign.

midpoint between 2 points :

we could use Pythagoras again for this, but the end result is so simple, we can skip this.

at the end the coordinates of the midpoint of 2 points (x1, y1) and (x2, y2) are

((x1+x2)/2, (y1+y2)/2)

find the other endpoint (x2, y2), when you have one endpoint (x1, y1) and the midpoint (xm, ym) :

from above you know

xm = (x1+x2)/2

2×xm = x1 + x2

x2 = 2×xm - x1

and in the same way

ym = (y1+y2)/2

2×ym = y1 + y2

y2 = 2×ym - y1

and you can read a graph, right ?

if not it is high time to learn that very simple and basic skill :

the x coordinate of a point is how many units right (positive) or left (negative) from the center point it is.

the y coordinate of a point is how many units above (positive) or below (negative) from the center point it is.

the center point is always (0, 0).

so, what else do you need ?

I am very busy explaining things. I should not spend my little time doing the basic calculations for you (that I could train a monkey to do).

so, please, oil your brain machinery by following the instructions and formulas using the actual numbers and see how the results build out of this.

if you run into further problems, please ask me for additional explanations.

8 0
3 years ago
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