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algol [13]
2 years ago
11

If a group of distinct objects can be arranged in 120 different ways, how many objects are there? A. 3 B. 4 C. 5 D. 6

Mathematics
2 answers:
Mademuasel [1]2 years ago
8 0
C........................
faust18 [17]2 years ago
4 0

Answer:  The correct option is (C) 5.

Step-by-step explanation:  Given that a group of distinct objects can be arranged in 120 different ways.

We are to find the number of objects in the group.

We know that a group of n distinct objects can be arranged in n! ways.

And, for a non-negative integer n, the factorial of n is defined as

n!=n(n-1)(n-2)~~.~~.~~.~~3.2.1

<u><em>Option (A)</em></u> :  If n = 3, then

n!=3!=3\times2\times 1=6\neq 120.

So, option (A) is incorrect.

<u><em>Option (B)</em></u> :  If n = 4, then

n!=4!=4\times 3\times2\times 1=24\neq 120.

So, option (B) is incorrect.

<u><em>Option (C)</em></u> :  If n = 5, then

n!=5!=5\times4\times3\times2\times 1=120.

So, option (C) is correct.

<u><em>Option (D) </em></u>:  If n = 6, then

n!=6!=6\times5\times 4\times3\times2\times1=720\neq 120.

So, option (D) is incorrect.

Thus, (C) is the correct option.

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serious [3.7K]

17.

x = -2 is not a solution of -1 < x < 5 because -2 < -1 (-1 < -2 < 5 FALSE).

18.

m = 5 is a solution of 5 ≤ m because 5 ≤ 5 ( 5 ≤ m → m ≥ 5 greater than 5 or equal 5, 5 is equal 5)

19.

k = 10 is not solution of 2k - 3 < 1 because:

put the value of k to the inequality:

2(10) - 3 < 1

20 - 3 < 1

17 < 1 FALSE

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2 years ago
I’m so bad at slope
Travka [436]

Answer:

So slope 1 would be positive

Slope 2 would be negative

Slope 3 would be zero

Step-by-step explanation:

If the slope is moving up from left to right, then it is positive

If the slope is moving down from left to right, then it is negative

If the slope is a vertical line and is not moving left/right, then it is undefined

If the slope is a horizontal line and is not moving up/down, then it is zero

So slope 1 would be positive because it is moving up from left to right.

Slope 2 would be negative because it is moving down from left to right.

Slope 3 would be zero because it is a horizontal line that is not moving up or down.

Hope this helped!

7 0
3 years ago
Write the equation of the line in slope-intercept form using y=mx+b​
AnnZ [28]
It looks like it goes through (0,-3) and (1,2), so the gradient is (change in y)/(change in x) ->
(-3-2)/(0-1) = 5
So y=5x+b

Then as we know it passes the y axis at (0,-3) so b= -3

So we have y=5x-3
3 0
2 years ago
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kykrilka [37]

Answer:

4 jumps

Step-by-step explanation:

5 points per jump and 20 points in total.

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2 years ago
The area of triangle formed by points of intersection of parabola y=a(x−1)(x−4) with the coordinate axes is 3. Find a if it is k
n200080 [17]

Answer:

The value of a will be  a=-\frac{1}{2}

Step-by-step explanation:

Start by graphing the parabola and  the three points of the triangle. These points are at intersections of y=a(x-1)(x-4) and the axes

so the y = 0 points are (1,0) and (4,0).

The x = 0 intersection is when y=a(-1)(-4) or (0,4a)

The base and height of this triangle are

The base would be the distance between the y=0 intersections and the height would be the y value of the other vertex.

Hence, base=3 units and height = 4a units. Thus, area can be calculated as

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hence,  a=-\frac{1}{2}

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3 years ago
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