HELP ME PLZZZZZZZZZZ
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Well you could round it to the 4th decimal, which would be 2.7183
That as a mixed number would be
That as a mixed number would be
Check the picture below, so, those red ones are the midpoints you found.
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) \stackrel{midpoint}{JK}&({{ -1}}\quad ,&{{ 2}})\quad % (c,d) \stackrel{midpoint}{ML}&({{ 2}}\quad ,&{{ -2}}) \end{array} \\\\\\ d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\implies d_2=\sqrt{[2-(-1)]^2+[-2-2]^2} \\\\\\ d_2=\sqrt{(2+1)^2+(-4)^2}\implies d_2=\sqrt{9+16}\implies d_2=5](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0A%5Cstackrel%7Bmidpoint%7D%7BJK%7D%26%28%7B%7B%20-1%7D%7D%5Cquad%20%2C%26%7B%7B%202%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0A%5Cstackrel%7Bmidpoint%7D%7BML%7D%26%28%7B%7B%202%7D%7D%5Cquad%20%2C%26%7B%7B%20-2%7D%7D%29%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%5Cimplies%20d_2%3D%5Csqrt%7B%5B2-%28-1%29%5D%5E2%2B%5B-2-2%5D%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Ad_2%3D%5Csqrt%7B%282%2B1%29%5E2%2B%28-4%29%5E2%7D%5Cimplies%20d_2%3D%5Csqrt%7B9%2B16%7D%5Cimplies%20d_2%3D5)
now, that many units are each distance for those "medians", hmmm now, recall that each unit is meant to be 10 meters, so, just multiply each by 10, to get how many meters long each one is.
now, that many units are each distance for those "medians", hmmm now, recall that each unit is meant to be 10 meters, so, just multiply each by 10, to get how many meters long each one is.