Question

Use the parabola tool to graph the quadratic function f(x)=−12x2+7. Graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

Answer 1

First we find the vertex of parabola $f(x)=-12 x^{2} +7$

The vertex of parabola is $( \frac{-b}{2a},f( \frac{-b}{2a}))$
Here,
b = coefficient of x term
a = coefficient of x² term

For given parabola, b = 0 , a = -12

So,
$\frac{-b}{2a}= \frac{0}{-24} =0$

And,

$f( \frac{-b}{2a} )=f(0) = -12(0)+7=7$

Thus the vertex of parabola is (0, 7)

To find another point on parabola, substitute x by 1.

$f(1)=-12( 1^{2}) +7=-12+7=-5$

So the second point on parabola is (1,-5)

The plot of parabola is shown in image below:

Answer 2

Here are a bunch of CORRECT answers, your answer is somewhere in there. For the first CORRECT answer the second point is -5,-9. Don't make the same mistake I did on question 3, but it still shows the correct answer. I love to help.