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3 years ago

-8d-5d+7d=72 can you help me figure out d

Mathematics

1 answer:

Kryger [21]3 years ago

8 0

Answer:

d = -12

Step-by-step explanation:

Add -8 -5 +7

take that number : -6

72 divided by -6 = -12

d = -12

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When x pounds of force is applied to one end of a lever that is L feet long, the resulting force y on the other end is

nadezda [96]

The question is worded poorly, but it looks like you have a lever in equilibrium, with a force x at a distance d from the fulcrum, and a force y at a distance L - d from the fulcrum. You already have the equilibrium formula for this situation:

xd = y(L - d)

If you know x, y, and d, you can solve for the length L.

3 0

3 years ago

What is the common factor among xy2 and x2y ?

Nikolay [14]

Answer:

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3 years ago

If you take half my age and add 7, you get my age 13 years ago. How old am I?

mestny [16]

Answer:

You are currently 40 years old

Step-by-step explanation:

Let's say the current age is represented by the variable x.

x = current age

The question says that "if you take half my age and add 7, you get my age 13 years ago"

This can be represented like this:

1/2(x) + 7 = x - 13

Now we solve for x using basic algebra:

1/2(x) = x - 20

-1/2(x) = -20

x = 40

To check if this is correct, plug it back into the equation and see if both sides equal each other:

1/2(40) + 7 = (40) - 13

20 + 7 = 27

27 = 27

Hope this helps (●'◡'●)

3 0

3 years ago

Help me with these questions

Elena L [17]

Answer: a = 4, b = 163,422

Step-by-step explanation:

$P = P_{0} e^{kt}$ P is the new population, P₀ is the initial population, k is the growth rate, t is the time elapsed.

Part a) What do we know?

P = 7003

P₀ = unknown

k = .21 (converted 21% into a decimal)

t = 36 yrs (2006 - 1970)

$P = P_{0} e^{kt}$ need to solve for P₀

$7003 = P_{0} e^{(.21)(36)}$

$7003 = P_{0} e^{7.56}$

7003 = P₀ (1920)

$\frac{7003}{1920} = P_{0}$

3.6 = P₀

rounded to the nearest whole number = 4

Part b) What do we know?

P = unknown

P₀ = 7003

k = .21 (converted 21% into a decimal)

t = 15 yrs (2021 - 2006)

$P = P_{0} e^{kt}$ need to solve for P₀

$P = 7003 e^{(.21)(15)}$

$P = 7003 e^{3.15}$

P = 7003(23.33)

P = 163,422.46

rounded to the nearest whole number = 163,422

*************************************************************

Answer: 2, -1

Step-by-step explanation:

eˣ² = eˣ * e²

eˣ² = eˣ⁺²

x² = x + 2

x² - x - 2 = 0

(x - 2)(x + 1) = 0

x - 2 = 0 or x + 1 = 0

x = 2 or x = -1

Check both answer for validity:

eˣ² = eˣ⁺²

e⁴ = e⁴ or e¹ = e¹

TRUE TRUE

*****************************************

Answer: 0 = ln 1

Step-by-step explanation:

$e^{-10} = \frac{1}{e^{10}}$

$ln(e^{-10}) = ln(\frac{1}{e^{10}})$

-10 = ln 1 - 10 log rules say division is subtraction

0 = ln 1

5 0

3 years ago

What is the area of a circle is the radius is 8

Shalnov [3]

When the radius is 8, the area would be 201.06

Area of circle = pi x radius² (pi x 8²)

8 0

3 years ago

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