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Minchanka [31]
4 years ago
9

Using the numbers 5, 8, and 24, create a problem using no more than four operations (addition, subtraction, multiplication, divi

sion, square, square root, cube, cube root) where the solution will be an irrational number. Explain why the result of your operations is an irrational number.
Mathematics
1 answer:
Vilka [71]4 years ago
6 0
How about (8+5)/25...?
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A coin is flipped 50 times and land on heads 33 times what is the relative frequency it lands on heads
alex41 [277]

Answer:

.66

Step-by-step explanation:

Divide the times it landed on its head by the times it was flipped.

6 0
3 years ago
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Plz help me ill give u brainlist
iren2701 [21]
Total Area = 2( 32 x 79) + (26 x 42) = 6148 m²

Number of 4 m² = 6148 ÷ 4 = 1537

Answer: The zoo can have 1537 plants.
8 0
4 years ago
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Find the product of -9xy(4x^5y^3-4x^2y)
MArishka [77]
The product is

-36x^6y-9xy^3+36x^3y-9xy^2
6 0
4 years ago
Pls help ill give brainliest
Ymorist [56]

Answer:

\boxed {\boxed {\sf (5g^2+2)(2g-5)}}

Step-by-step explanation:

We are given the expression:

10g^3-25g^2+4g-10

There are no common factors between the four numbers, however the first two have a common factor and the last two do too. Therefore, we can factor by grouping.

Group the first two terms and the last two.

(10g^3-25g^2)+(4g-10)

Find the greatest common factor (GCF) of the first group. It is 5g². Factor it out of the first group. You can do this by dividing both terms by the GCF.

  • 10g³/5g²= 2g
  • -25g²/5g² = -5

5g^2 (2g-5) + (4g-10)

Repeat with the second group. The GCF is 2.

  • 4g/2 = 2g
  • -10/2= -5

5g^2 (2g-5) + 2(2g-5)

There is another GCF: 2g-5. We can factor this out of both terms.

  • 5g²(2g-5)/2g-5= 5g²
  • 2(2g-5)/ 2g-5=2

(5g^2+2)(2g-5)

This cannot be factored further, so it is the answer.

4 0
3 years ago
Which of these polynomial equations is of least degree and has -1, 2, and 4 as three of its roots?
kvasek [131]

Answer:

x^3 - 5 x^2 + 2 x + 8 = 0

Step-by-step explanation:

Solve for x over the real numbers:

x^3 - 5 x^2 + 2 x + 8 = 0

The left hand side factors into a product with three terms:

(x - 4) (x - 2) (x + 1) = 0

Split into three equations:

x - 4 = 0 or x - 2 = 0 or x + 1 = 0

Add 4 to both sides:

x = 4 or x - 2 = 0 or x + 1 = 0

Add 2 to both sides:

x = 4 or x = 2 or x + 1 = 0

Subtract 1 from both sides:

Answer: x = 4 or x = 2 or x = -1

6 0
3 years ago
Read 2 more answers
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