Given that the area of the sector is given by: A=3.142r² S/360 where: r is the radius S is the angle measure of the sector If Mia solved the equation for S, the equations that she wrote would be found as follows;
From A=3.142r² S/360 making S the subject by first dividing both sides by 3.142r^2 we shall have: A/3.142r²=S/360 next we multiply both sides by 360 360×A/3.142r²=S/360×360 this will give us (360A)/(3.142r²)=S therefore the equation that Mia will get is: S=(360A)/(3.142r²)
FOIL method First: u squared times u squared equals to u to the fourth. Outer and Inner: 8u squared + u squared equal 9u squared. Remember, the exponents don't change when adding! Last: 8 times 1 equals 8
Because the y intersect is located at (0,2) we know that the b value in the formula y=mx + b is 2 and using rise over run we determine the slope to be -1/3