<span>Look
for the sum of 56 and 64, written as the product of its GCF and another sum.
First, let’s find the greatest common factor of both given numbers:
=> 56 = 1, 2, 4, 7, 8, 13, 28 and 56
=> 64 = 1, 2, 4, 8, 16, 32, and 64
Now, we need to find the greatest common factor between the two numbers. The GCF
of the 2 numbers is 8.
=> 56 / 8 = 7
=> 64 / 8 = 8
=> 56 + 64 = 120
=> (8 x 7) + (8 x 8)
=> 56 + 64
=> 120.</span><span>
</span>
Answer:
The first one
Step-by-step explanation:
The number line is supposed to show the product of 2 and five, the arrow will start at 0 because 5 times 0 is 0 then it will go to 5 because 5 times 1 is 5, then another arrow will start at 5 and point at 10 because 5 times 2 is 10
The second option points backwards which would be if you were dividing 10 by 5
The third option starts at negative 10 so it shows -10 divided by -5
the last option starts at 0 and goes to -10 so it shows -5 multiplied by 2
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
<span>Find
the speed of each car.
Let a be the first car
Let b be the second car
=> a = x miles per hour
=> b = x + 12 miles per hour
=> 2 (x+ x + 12) = 232 miles per hour
=> 2x + 12 = 232
=> 2x + 12 = 116
=> 2x = 116 - 12
=> 2x / 2 = 104 / 2
=> x = 52 (speed of Car A)
=> 52 + 12 = 64 miles per hour (speed of Car B)</span>
Step-by-step explanation:
slope another name for gradient