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attashe74 [19]
3 years ago
11

Evaluate 7x-1 when x= 3

Mathematics
2 answers:
irina1246 [14]3 years ago
5 0

Hello there! And welcome to brainly . com, your #1 asking and answering site!

Answer: 20

<em>Why?</em>

So we need to substitute x for 3, so do that. (7x-1 => 7 * 3 - 1) Multiply 7 by 3. (7 * 3 == 21) Finally, subtract by one. (21 - 1 == 20) Therefore, your answer is 20.

Hope this helped you, and have a beautiful day!! ♥

kondaur [170]3 years ago
3 0

7x - 1 = 20

7 times 3 is 21, 21 minus 1 is 20

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Square has side lengths of 13 units. Point lies in the interior of the square such that units and units. What is the distance fr
romanna [79]

The distance from E to side AD is 25/13.

<h3>What is a distance?</h3>
  • The length of the line connecting two places is the distance between them.
  • If the two points are on the same horizontal or vertical line, the distance can be calculated by subtracting the non-identical values.

To find what is the distance from E to side AD:

  • If you draw a diagram, you'll see that triangle AEB is a right triangle with lengths 5, 12, and 13.
  • Let's call F the point where E meets side AD, so the problem is to find the length of EF.
  • By Angle-Angle Similarity, triangle AFE is similar to triangle BEA. (the right angles are congruent, and both angle FAE and ABE are complementary to angle BAE)
  • Since they're similar, the ratios of their side lengths are the same.
  • EF/EA = EA/AB (they're corresponding side lengths of similar triangles).

Substitute them with known lengths:

  • EF/5 = 5/13
  • EF = 5 × (5/13) = 25/13

Therefore, the distance from E to side AD is 25/13.

Know more about distance here:

brainly.com/question/2854969

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The correct answer is given below:
Square ABCD has side lengths of 13 units. Point E lies in the interior of the square such that AE=5 units and BE=12 units. What is the distance from E to side AD? Express your answer as a mixed number.

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