X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x=

or x=

ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute

=

=

=

=

so the answers for x are

and

which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0
Answer:

Step-by-step explanation:
Given
See attachment
Required
The area of the semicircle
First, we calculate the hypotenuse (h) of the triangle
Considering only the triangle, we have:
--- cosine formula
Make h the subject



The area of the semicircle is then calculated as:

This gives:



**All 3 angles of a triangle have a sum of 180°.**
So if 2 of those 3 angles are 62.5°, you would just subtract that by 180°.
180 - 62.5 = 117.5
The third angle would have to be 117.5°.