Can someone please help me with question 6

What number should be placed in the box to help complete the division calculation?

Anarel [89]

344 should be placed in the box

3 0

3 years ago

Johanna receives a report that says her typing speed is 65 words per minute. She knows that she made 4 errors in the 5-minutes t

oksian1 [2.3K]

How many words did she type in 5 minutes ?

65x5 - 4 = 325 - 4 = 321 words

7 0

3 years ago

How do u do this plz help me, also can some one tell me what is a adjacent angle and a vertical angle plz

Vsevolod [243]

Adjacent AnglesTwo angles areAdjacent if they have a common side and a common vertex. ... VerticalAnglesVertical Angles are the anglesopposite each other when two lines cross.They are called "Vertical" because they share the same Vertex.Vertical Angles are Congruent/equivalent

6 0

3 years ago

HELP!!! BRAINLIEST!!The expression on the left side of an equation is shown below.

storchak [24]

Answer:

Expression that can be written in the box on the other side of the equation will be x

Step-by-step explanation:

The left side of equation is:

Simplifying the equation we get:

An equation has no solution when, we cannot find the value of x.

So, The order side of equation can be x

i.e,

So, expression that can be written in the box on the other side of the equation will be x

3 0

3 years ago

Sample Size for Proportion As a manufacturer of golf equipment, the Spalding Corporation wants to estimate the proportion of gol

Dima020 [189]

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by:

$t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

We can assume an estimated proportion of $\hat p =0.5$ since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56$

And rounded up we have that n=2663

6 0

3 years ago