If (x, y) is a solution to the system of equations, what is the value of y?

What does it mean if the slopes are different

gladu [14]

Answer:

it means that they are 2 different lines on a cordinate plane

PLZ MARK BRAINLIEST

4 0

3 years ago

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Find the area of the circle to the nearest whole number, if necessary!

astra-53 [7]

Answer:

The circle has an area of about 1385 square mm.

Step-by-step explanation:

Let's recall that circles have an area that can be found with the following formula:

$A=\pi r^{2}$

where r is the radius of the circle.

Now, focus your eyes on the circle. We are shown that the diameter of this circle is 42 mm, but we only want the radius. Since the radius is half the diameter, the radius is 21 mm. Now, we can solve for the area of the circle.

$A=\pi (21)^2\\A=441\pi \\A=1385.44236...$

So, to the nearest whole number, the area of the circle is 1385 square mm.

5 0

2 years ago

Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF

Contact [7]

Find the equation of the inverse.

$y = {2}^{x + 5} - 6$

we have

$y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6$

step 1

Exchange the variables

x for y and y for x

$x=\{2\}^{\{y+5\}}-6$

step 2

Isolate the variable y

$(x+6)=2^{(y+5)}$

apply log both sides

$\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\ \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}$

step 3

Let

$f^{(-1)}(x)=y$

therefore

the inverse function is

$f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5$

7 0

1 year ago

What is the product of (x-2)(x+2)?

Ilya [14]

Answer:

The difference of squares is (a - b)(a + b) = a² - b². Since a = x and b = 2, the answer is x² - 4.

6 0

3 years ago

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D(x)=(x^2-12x+20)/(3x)

krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

Explanation:

d(x) = $\frac{x^{2}-12x+20}{3x}$

= $\frac{(x-2)(x - 10)}{3x}$

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0

÷3 ÷3

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

(1/3)x - 4
3x) x² - 12x + 20
x²
-12x
-12x
20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4

6 0

3 years ago