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Fudgin [204]
3 years ago
13

How do I solve this? What do they mean

Mathematics
1 answer:
adell [148]3 years ago
8 0
Complimentary angles add to equal 90°. Write two equations to solve for two variable.
J + K = 90
J = K - 18

use substitution or elimination to solve
I will use substitution. substitute (K - 18) for J in the first equation to combine equations into one in only variable K.

(K - 18) + K = 90
2K - 18 = 90
2K = 90 + 18
2K = 108
K = 108/2
K = 54°

J and K are complimentary.
J + 54° = 90°
J = 36°
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The circumference =81.7
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What is a number factor of 24, but not a multiple of 6
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12 times 2 ..............................

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Owen had 3 different kinds of stickers that he wanted to put on paper. He put a bird sticker on every 30th paper, a sports stick
Semmy [17]
So the which page that will have the 3 sticker, we must solve the least common multiple of 30, 50, 60. <span>A common multiple is a number that is a multiple of two or more numbers. The common multiples of 3 and 4 are 0, 12, 24, ....</span>

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3 years ago
What number divided by 5 equals 6
djyliett [7]
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6 0
3 years ago
Read 2 more answers
Write an equation for an ellipse centered at the orgin, which has foci ( plus minus 3, 0) and co-vertices at (0, plus minus 4)
Vadim26 [7]

Answer:

The answer is below

Step-by-step explanation:

The co-vertices of an ellipse are the endpoints of the minor axis. The equation for an ellipse is given by:

\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2}=1

Where (h, k) is the center of the ellipse, (h, k±b) is the co-vertices, (h ± a, k) is the vertices, (h ± c, k) is the foci and c² = a² - b²

Since the center is the origin, hence (h, k) = (0, 0). i.e h = 0, k = 0.

Foci = (h ± c, k) = (± c, 0) = (±3, 0). c = 3

co-vertices = (h, k±b)  = (0, ±b)  = (0, ±4). b = 4

c² = a² - b²

a² = c² + b²

a² = 3² + 4² = 25

a = 5

Therefore the equation of the ellipse is:

\frac{x^2}{5^2} +\frac{y^2}{4^2}=1 \\\\\frac{x^2}{25} +\frac{y^2}{16}=1

6 0
3 years ago
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