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Fudgin [204]
2 years ago
13

How do I solve this? What do they mean

Mathematics
1 answer:
adell [148]2 years ago
8 0
Complimentary angles add to equal 90°. Write two equations to solve for two variable.
J + K = 90
J = K - 18

use substitution or elimination to solve
I will use substitution. substitute (K - 18) for J in the first equation to combine equations into one in only variable K.

(K - 18) + K = 90
2K - 18 = 90
2K = 90 + 18
2K = 108
K = 108/2
K = 54°

J and K are complimentary.
J + 54° = 90°
J = 36°
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A piece of green jade has a mass of 23.401 g.if the sample of jade displaces 50.0 ml of water to 56.5 ml in a 100 ml graduated c
OleMash [197]

we know that

The density is equal to the formula

Density=\frac{mass}{volume}

in this problem we have

mass=23.401\ gr

<u>Find the volume of a piece of green jade</u>

Volume=56.5\ ml-50.0\ ml=6.5\ ml

Substitute the values in the formula of density

Density=\frac{23.401}{6.5}

Density=3.60\frac{gr}{ml}

therefore

<u>the answer is</u>

Density=3.60\frac{gr}{ml}

3 0
3 years ago
1.) The graph of g(x) = ax? opens downward and is narrower than the graph of f(x) = x? Which of the following
laila [671]

Answer:

C. -5

Step-by-step explanation:

for g(x) =ax and f(x) = x, both are linear function. There is nothing to be upward or downward and both are lines nothing to compare its narrowness.

If g(x) = ax² vs f(x) = x²

Then a = -5 is the answer (-: downward and 5: vertical stretch)

8 0
2 years ago
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
What are the side lengths of the equilateral triangle?
Alchen [17]

5x  +  (6x - 5) + (3x + 10) = 360

5x  + 6x - 5 + 3x + 10 = 360

11x - 5 + 3x + 10 = 360

14x + 5 = 360

14x = 360 - 5

14x = 355

x = 25.36

<h2><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u></h2>

x = 25.36

5x = 5 \times 25.36 = 126.8

6x - 5 = 6 \times 25.36 - 5 = 147.16

3x + 10 = 3 \times 25.36 + 10 = 86.08

4 0
3 years ago
Simplify [view attached image]
pav-90 [236]

<u>Given</u>:

The given expression is (\sqrt{5})( \sqrt[3]{5})

We need to simplify the given expression.

<u>Simplification</u>:

Let us simplify the given expression.

Rewriting the given expression, we have;

5^{\frac{1}{2}} \cdot 5^{\frac{1}{3}}

Let us apply the exponent rule \:a^b\cdot \:a^c=a^{b+c}, we get;

5^{\frac{1}{2}+\frac{1}{3}}

Taking LCM, we have;

5^{\frac{3+2}{6}}

Simplifying, we get;

5^{\frac{5}{6}}

Thus, the simplified value of the given expression is 5^{\frac{5}{6}}

Hence, Option a is the correct answer.

6 0
3 years ago
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