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daser333 [38]
3 years ago
8

This is similar to a problem in the textbook. After a foreign substance is introduced into the blood, the rate at which antibodi

es are made is modeled by f(t)=19t3t2+7 where f(t) is in thousands of antibodies per minute, and t is measured in minutes with 0≤t≤10. Assuming that there are no antibodies present at time t=0, find the total number of antibodies in the blood at the end of 10 minutes. Round your answer to two decimal places.
Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

We will find the number of antibodies by integrating the function:

∫

f

0

f

′

(

t

)

=

∫

60

0

27

t

8

t

2

+

3

d

t

Integrating both sides we get:

f

=

27

16

ln

(

8

t

2

+

3

)

Now let us plug-in the bounds we get:

Step-by-step explanation:

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PLEASE ANSWER! Given the functions f(x) = x2 + 6x - 1, g(x) = -x2 + 2, and h(x) = 2x2 - 4x + 3, rank them from least to greatest
Ratling [72]

Answer:

<em>he rank from least to great based on their axis of symmetry: </em>

0, 1, -3 ⇒ g(x), h(x), f(x)

So, <em>option C</em> is correct.

Step-by-step explanation:

A quadratic equation is given by:

ax^2+bx+c =0

Here, a, b and c are termed as coefficients and x being the variable.

<em>Axis of symmetry can be obtained using the formula</em>

x = \frac{-b}{2a}

Identification of a, b and c in f(x), g(x) and h(x) can be obtained as follows:

f(x) = x^2 + 6x - 1

⇒ a = 1, b = 6 and c = -1

g(x) = -x^2 + 2

⇒ a = -1, b = 0 and c = 2

h(x) = 2^2 - 4x + 3

⇒ a = 2, b = -4 and c = 3

So, axis of symmetry in f(x) = x^2 + 6x - 1 will be:

x = \frac{-b}{2a}

x = -6/2(1) = -3

and axis of symmetry in g(x) = -x^2 + 2 will be:

x = \frac{-b}{2a}

x = -(0)/2(-1) = 0

and axis of symmetry in h(x) = 2^2 - 4x + 3 will be:

x = \frac{-b}{2a}

x = -(-4)/2(2) = 1

<em>So, the rank from least to great based on their axis of symmetry: </em>

0, 1, -3 ⇒ g(x), h(x), f(x)

So, <em>option C</em> is correct.

<em>Keywords: axis of symmetry, functions</em>

<em>Learn more about axis of symmetry from brainly.com/question/11800108</em>

<em>#learnwithBrainly</em>

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