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3 years ago

Which statements about a square are always true?

Mathematics

2 answers:

blondinia [14]3 years ago

6 0

All of the answers are correct except the last one

VikaD [51]3 years ago

3 0

Answer:

The top three are correct! The last one is not.

Step-by-step explanation:

Each opposite side is directly parallel to each other.

All sides are congruent therefore making the second option true as well.

And it's diagonals do bisect each other.

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Find derivative: f(u) = arctan(u/(1+u)

VikaD [51]

F ` ( x ) =
$\frac{1}{1+ \frac{u ^{2} }{(1+u) ^{2} } } * ( \frac{u}{1+u})`= \\ = \frac{1}{ \frac{(1+u) ^{2}+ u^{2} }{(1+u) ^{2} } } * \frac{(u)`(1+u)-(1+u)` u}{(1+u) ^{2} } = \\ = \frac{(1+u) ^{2} }{(1+u) ^{2}+u ^{2} } * \frac{1+u-u}{(1+u) ^{2} } = \\ = \frac{1}{1+2u+2u ^{2} }$

6 0

3 years ago

What would be the answer to 8x^6/ 8x^5 =?

Lubov Fominskaja [6]

In dividing two equation with variables and exponent, First you must align or rearrange the equation and group them base on their variables but don't forget the sign of each variables. Second, proceed in dividing its quantity and then subtract its exponent to the other variables having the same. So by calculating it, the answer would be X or X^1

3 0

3 years ago

Helllppp porfavor:,)

tatuchka [14]

Answer:

1. x = 67.5

2. x = 2.5

3. x = 35.2

4. x = 2.0

5. x = 17.0

Step-by-step explanation:

Question 1

The proportion is set up in the form x/9 = 15/2. Multiply both sides by two to get rid of the two in the denominator on the right side. After doing so, multiply by 9 on both sides to get rid of the 9 in the denominator on the left:

2x/9 = 15

2x = 9(15)

Next solve for x:

2x = 135

x = 67.5

Question 2

The proportion is set up in the form 20/8.7 = 5.8/x. Multiply both sides by the second denominator, x, and then both sides by the first, 8.7. This will leave you with the work below:

20x/8.7 = 5.8

20x = 8.7(5.8)

Next, solve for x:

20x = 50.46

x = 2.523

Round to the nearest tenth:

x = 2.5

Question 3

The proportion is set up in the form 5/16 = 11/x. Multiply both sides by the second denominator, x, and then both sides by the first, 16. This will leave you with the work below:

5x/16 = 11

5x = 11(16)

Next, solve for x:

5x = 176

x = 35.2

Question 4

The proportion is set up in the form x/0.06 = 17/0.5. Multiply both sides by the second denominator, 0.5, and then both sides by the first, 0.06. This will leave you with the work below:

0.5x/0.06 = 17

0.5x = 17(0.06)

Next, solve for x:

0.5x = 1.02

x = 2.04

Round to the nearest tenth:

x = 2.0

Question 5

The proportion is set up in the form 29/x = 75/44. Multiply both sides by the second denominator, 44, and then both sides by the first, x. This will leave you with the work below:

29(44)/x = 75

29(44) = 75x

Next, solve for x:

1276 = 75x

x = 17.0133

Round to the nearest tenth:

x = 17.0

7 0

3 years ago

The perimeter of a rectangle room is 250 feet the length is 35 feet less than three times the width what is the length of the ro

raketka [301]

Perimeter of rectangle:
P = 2(L + W)
P = 250 (given)
L = 3W - 35 (given)

250 = 2(3W -35 + W) ↔ 125 = 4W - 35

4W = 125 +35 =160 And W = 40 ft
And L = 3x40 - 35 = 85 ft

6 0

3 years ago

14 plus 5(x plus 3) minus 7

Damm [24]

14+5(x+3)-7
14+(5x+15)-7
7+5x+15
5x+22

7 0

3 years ago