You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Step-by-step explanation:
Kayden:Kayah:Kayla:Michelle
2:3:4:3
2k+3k+4k+3k=36
12k=36
k=36:12
k= 3
Kayden- 2•3=6
Kayah- 3•3=9
Kayla= 4•3=12
Michelle= 3•3=9
Answer:
50 1/6% (50 and one sixth) or $22.92
Step-by-step explanation: