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3 years ago

What’s the remainder when p (x) is divided x+3

Mathematics

1 answer:

miss Akunina [59]3 years ago

5 0

p (x) is divided x+3 = 0

the remainder is 0

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Please find a solution to the following equations below and see if they have either one solution, no solution or infinite soluti

andreyandreev [35.5K]

Answer:

A. no solution

B. infinite solutions

C.one solution

D. no solution

8 0

3 years ago

Calculate the mean, median, and mode of the following set of data. Round to the nearest tenth. 7, 3, 2, 1, 13, 8, 1, 5, 14, 11,

zysi [14]

Answer:

Mean = 7.3, median = 7, mode = 1.

Step-by-step explanation:

First arrange the data in order:

1 1 2 3 5 7 8 11 13 14 15

There are a total of 11 values.

Median = middle value = 7.

Mode = the most common number = 1.

Mean = sum / 11

= 80 / 11

= 7.3.

5 0

4 years ago

Anyone know how to do this?

lesya [120]

To solve this, we need to use our trignometric functions;

⇒ look at the diagram attached

Let's examine what the problem wants:

hypotenuse (longest side) of the triangle

Let's examine what the problem gives us:

side adjacent to the 45-degree angle
angle that has measure of 45-degrees

Let's solve:

$sin(45)=\frac{5}{x} \\5=x*sin(45)\\x = \frac{5}{sin(45)} \\x=7.07$

Answer: 7.1 (rounded to nearest tenth)

Hope that helps!

6 0

2 years ago

Read 2 more answers

A sample of 64 was taken from a population, with the mean of the sample being 119 and the standard deviation of the sample being

Fofino [41]

We have the sample size, sample mean and the sample standard deviation. Since the population standard deviation is not know, we will use t-distribution to find the confidence interval.

The critical t value for 95% confidence interval and 63 degrees of freedom is 1.998.

The 95% confidence for the population mean will be:

$(119-1.998 *\frac{16}{ \sqrt{64} } ,119+1.998 *\frac{16}{ \sqrt{64} }) \\ \\ 
=(115.004, 122.996) \\ \\=(115,123)$

Thus, the 95% confidence interval for the population mean will be (115,123)

So, option A is the correct answer

6 0

3 years ago

Find a counterexample: Two sides of a

Shkiper50 [21]

Answer: Any isosceles triangle is a counter example. More specifically, a triangle with sides 7, 7 and 3

When forming your triangle, make sure you apply the triangle inequality theorem. This is the idea where adding any two sides leads to a result larger than the third side. So we have

7+7 = 14 which is larger than 3

7+3 = 10 which is larger than 7

By definition, an isosceles triangle has two congruent sides. Some books say "at least 2 congruent sides", but I'll go with the first definition. If you want all three sides to be congruent, then you'd go for the term "equilateral".

6 0

3 years ago