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3 years ago

A pigeon can fly at a speed of 84 kilometers per hour. How long does it take the pigeon to fly 7 kilometers?

Mathematics

1 answer:

Serhud [2]3 years ago

3 0

The pigeon can fly 7 kilometers in around 8-9 minutes

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Mr. Perrins’s class sold packs of peanut butter cookies for $2.35 each and Mr. Woods’s class sold bottles of milk for $1.34 each

sergey [27]

Answer:

1. Solution = (4,3) and they intersect.

2. Solution = Infinite, this means that the lines overlap each other constantly.

3. Equations = x + y=73 and 2.35x + 1.34y = 141.25

PB Cookies made $101.05

Milk Bottles made $40.02

The cookies made more by $61.03

Step-by-step explanation:

Took the test and got 100%.

6 0

2 years ago

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The BlueSky Airlines has sold tickets for his plane to travel from Savannah to Atlanta. This plane carries 115 passengers. Howev

oee [108]

Answer:

it would be day 4 because if u add all of the tickets up once you get to day 5 it goes over 115

Step-by-step explanation:

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3 years ago

If f(x) = 2(3x) + 1, what is the value of f(2)?

Over [174]

F(2)=2(3*2)+1
f(2)=2(6)+1
=13
answer is 13

4 0

3 years ago

X^2- 11 = 70 I need help on how to solve this

brilliants [131]

Answer: Add 11 to the other side of the equation, giving you 81. Then, since x is square you are going to need to square root both sides ( $\sqrt{x}$ this symbol). When you do that, you should get what x is! Let me know if you still need help!

6 0

2 years ago

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Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar

Brrunno [24]

The distance between the two points is $d=8.6m$

The polar coordinate of A is $\left(4.47,296.57\right)$

The polar coordinate of B is $\left(4.24,135\right)$

Explanation:

The two points are $A(2,-4)$ and $B(-3,3)$

The distance between two points is given by,

$d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6$

Thus, the distance between the two points is $d=8.6m$

The polar coordinates of A can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $A(2,-4)$ , we get,

Distance = $\sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43$

To make the angle positive, let us add 360,

$\theta=360-63.43=296.57$

The polar coordinate of A is $\left(4.47,296.57\right)$

Similarly, The polar coordinate of B can be written as $(Distance, tan^{-1} \frac{y}{x} )$

Distance = $\sqrt{x^{2} +y^{2} }$

Substituting $B(-3,3)$ , we get,

Distance = $\sqrt{(3)^{2}+(3)^{2}}=4.24$

$tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45$

To make the angle positive, let us add 360,

$\theta=180-45=135^{\circ}$

The polar coordinate of B is $\left(4.24,135\right)$

5 0

3 years ago