
You pass the free terms wich don't contain 'x' in the othe part of the equal with changed signe ans the same for the terms wich contain x.
The value of 
<u>Solution:</u>
In the notation g(x) we know that whatever is put in the parentheses is what we replace for x. In the given situation, since it is g(b-5) we have to replace every x in the function with b-5. That is if,

then, 

On solving we get,


Answer:
×=1
Multiply both sides of the equation by 12, the least common multiple of 4,3.
3x+4(x−1)=3
Use the distributive property to multiply 4 by x−1.
3x+4x−4=3
Combine 3x and 4x to get 7x.
7x−4=3
Add 4 to both sides.
7x=3+4
Add 3 and 4 to get 7.
7x=7
Divide both sides by 7.
x=
7
7
Divide 7 by 7 to get 1.
x=1
You Have Passed Thy Test!!! BADAAAA (\•o•/)